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Allisa [31]
3 years ago
7

What is the equation of the line that passes through (0-2) and has a slope of 0?

Mathematics
1 answer:
harina [27]3 years ago
5 0

\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{-2})~\hspace{10em} \stackrel{slope}{m}\implies 0 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-2)}=\stackrel{m}{0}(x-\stackrel{x_1}{0})\implies y+2=0\implies y=-2

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Plss answer my question..<br><br>​
Kipish [7]

Answer:

<em>Gradient of KL = 2</em>

Step-by-step explanation:

From the diagram, we are to calculate the gradient of KL. Gradient is salso known as the slope of the line.

Gradient of KL = ΔOK/ΔOL

Given

OK = 2OL

Substitute into the formula

From the diagram, ΔOL = -5

ΔOK = 2ΔOL

ΔOK = 2(-5)

ΔOK = -10

Hence;

Gradient = -10/-5

<em>Gradient of KL = 2</em>

<em></em>

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3 years ago
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6 0
2 years ago
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castortr0y [4]

Step-by-step explanation:

Each interior angle=140°

(n-2)180°/n=140°

180°n-360°/n=140°

180°n-360°=140°n

180°-140°=360°

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Hence, the number of sides of the polygon is 9.

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Answer:

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Step-by-step explanation:

Attached is the full question

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