A set of equation can be set up: a=b+15 3(a+b)=345 where a is the faster and b is the slower bus. substitute b+15 into the second equation, so 6b+45=345, and 6b=300, therefore b=50. we can then figure out that a=65
The faster bus can be expressed with x+15=y where x is the rate of the slower bus and y is the rate of the faster bus. The buses travel for 3 hours, 345 miles apart. So it becomes 3y + 3x = 345 Substitute in the value for y with x+15 and you get 3(x+15) + 3x = 345 And afterwards, you just solve for x (WORK) 3x + 45 + 3x = 345 (Distribution) 6x + 45 = 345 (Combine like terms) 6x = 300 (Subtraction) x = 50 (Division) The rate of the slower bus is 50 mph, and plug it in for the equation for the faster bus. x + 15 = y (50) + 15 = y y = 65 The rate of the faster bus if 65 mph.
Hi there! An average person ate 200.8 pounds of meat, so we would multiply that number by 3 to see how much meat the family ate altogether. 200.8 * 3 is 602.4. There. A family of 3 would eat 602.4 pounds of meat in a year.
