Answer:
The number of messages that will cost same both plans is <u>1000</u>.
Step-by-step explanation:
Given,
For 1st offer:
Total number of messages = 500
Charge of each message after 500 messages = $0.10
For 2nd offer:
Total number of messages = 400
Charge of each message after 400 messages = $0.20
We need to find out the number of messages can be sent for equal cost of both plans.
Solution,
Let the number of messages be 'm'.
So For 1st offer:
Total cost 'c' is equal to fixed cost for 500 messages plus charge of each message multiplied with number of messages.
framing in equation form, we get;

Again for 2nd offer:
Total cost 'c' is equal to fixed cost for 400 messages plus charge of each message multiplied with number of messages.
framing in equation form, we get;

Now the question said that the charge would be the same.
So we can say that;

On combining the like terms, we get;

Now using multiplication property, we will multiply both side by '10' and get;

Hence The number of messages that will cost same both plans is <u>1000</u>.