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3 years ago

Find the function rule X= -2,-1,0,1,2 Y= 9,4,-1,-6,-11

Mathematics

2 answers:

anygoal [31]3 years ago

6 0

Answer:

The function rule for x is +1 and y is -5

Step-by-step explanation:

The function rule is basically the change for the set of numbers, like how x = 1, 2, 3, the function rule is +1, it's just the rate of change for the set of numbers.

pshichka [43]3 years ago

6 0

Answer:

x=1

y=-5

Step-by-step explanation:

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Evaluate the line integral, where C is the given curve. (x + 6y) dx + x2 dy, C C consists of line segments from (0, 0) to (6, 1)

Dima020 [189]

Split $C$ into two component segments, $C_1$ and $C_2$ , parameterized by

$\mathbf r_1(t)=(1-t)(0,0)+t(6,1)=(6t,t)$

$\mathbf r_2(t)=(1-t)(6,1)+t(7,0)=(6+t,1-t)$

respectively, with $0\le t\le1$ , where $\mathbf r_i(t)=(x(t),y(t))$ .

We have

$\mathrm d\mathbf r_1=(6,1)\,\mathrm dt$

$\mathrm d\mathbf r_2=(1,-1)\,\mathrm dt$

where $\mathrm d\mathbf r_i=\left(\dfrac{\mathrm dx}{\mathrm dt},\dfrac{\mathrm dy}{\mathrm dt}\right)\,\mathrm dt$

so the line integral becomes

$\displaystyle\int_C(x+6y)\,\mathrm dx+x^2\,\mathrm dy=\left\{\int_{C_1}+\int_{C_2}\right\}(x+6y,x^2)\cdot(\mathrm dx,\mathrm dy)$

$=\displaystyle\int_0^1(6t+6t,(6t)^2)\cdot(6,1)\,\mathrm dt+\int_0^1((6+t)+6(1-t),(6+t)^2)\cdot(1,-1)\,\mathrm dt$

$=\displaystyle\int_0^1(35t^2+55t-24)\,\mathrm dt=\frac{91}6$

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3 years ago

Solve the equation.round to the nearest thousandths -5+2in(3x)=5

Crank

What is the "in" for in your equation? Repost.

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3 years ago

Find the zeros of the function. Write the smaller solution first, and the larger solution second.

Mama L [17]

It is the correct
Just take it easy

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3 years ago

Can someone help me with these please?

saul85 [17]

Point-slope form: y-y1 = m(x-x1)

Standard form: ax + by = c

Slope-intercept form: y = mx+b

Start by finding the slope. We know it is negative since the line is decreasing. The slope is -4/3.

To create point-slope form, we need to get one point from the graph. Let's use (3,0).

$y = -\frac{4}{3}(x-3)$

To create slope-intercept form, we need the slope and the y-intercept. The y-intercept is the point where our equation crosses the y-axis. For this equation, it is 4.

$y = -\frac{4}{3}x + 4$

To get standard form, solve the equation in terms of C.

Point-slope form: y = -4/3(x-3)

Slope-intercept form: y = -4/3x + 4

Standard form: 4/3x + y = 4

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