Pare a.) $70 is what he would have left. Since each trip is $14 you would multiply that by the amount of times he went which was 11. 14x11 is $154. But you need what he has left so you take his total amount $224-$154 and get $70.
Part b.) 16 times. He has $224 total. You want to find out how many times he can go on the tool roads. We know the toll roads cost $14 each time. So you do $224/14 and get an even amount of 16. He would be able to use it 16 times before he have no money left.
Answer:
hope this might be useful
Idk what linear combination is but you can solve this way:
3x+y=4
-2x-y=-5
x=-1
3(-1)+y=4
-3+y=4
y=7
So x=-1 and y=7
Answer:
#5 x=8, #6 x=5
Step-by-step explanation:
Theyre vertical so for number 5 you would have the equation
5x+15=55
-15 -15 from both sides
5x=40
divide by 5 from both sides and you get
x=8
Same thing vertical so you would have
16x+7=87
-7 -7 from both sides
16x=80
divide by 16 from both sides
x=5
Answer:
18 boys
Step-by-step explanation:
we add 2 and 3 because they are equal parts:
2+3=5
Then we divide 45 by 5 because we want to find what 1 part equals"
45/5=9
We now do 9*2 to get an answer of:
9*2=18
hope this makes sense!
