WHAT IS THE SLOPE OF THE LINE SHOWN BELOW

Mathematics

2 answers:

lubasha [3.4K]2 years ago

5 0

Answer: D $\dfrac{6}{5}$

Step-by-step explanation:

The slope of a line passing through two points (a,b) and (c,d) is given by :-

$\text{Slope}=\dfrac{d-b}{c-a}$

From the given figure, we can see that the line is passing from the points (-5, - 1) ans (5,11).

Then , the slope of the given line will be :-

$\text{Slope}=\dfrac{11-(-1)}{5-(-5)}\\\\\Rightarrow\text{Slope}=\dfrac{12}{10}=\dfrac{6}{5}$

Hence, the slope of the given line = $\dfrac{6}{5}$

quester [9]2 years ago

4 0

Slope is rise over run. So you "rise" 6 spaces from -1 to 5 and then you "run" 5 spaces to the right i believe it will be 6/5.

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Suppose that the probability that any particle emitted by a radioactive material will penetrate a certain shield is 0.01. If 10

AnnyKZ [126]

Answer:

a)P=0.42

b) $n\geq 297$

Step-by-step explanation:

We have a binomial distribution, since the result of each experiment admits only two categories (success and failure) and the value of both possibilities is constant in all experiments. The probability of getting k successes in n trials is given by:

$P=\begin{pmatrix}n\\ k\end{pmatrix} p^k(1-p)^{n-k}=\frac{n!}{k!(n!-k!)}p^k(1-p)^{n-k}$

a) we have k=2, n=10 and p=0.01:

$P=\frac{10!}{2!(10!-2!)}0.01^2(1-0.01)^{10-2}\\P=\frac{10!}{2!*8!}0.01^2(0.99)^{8}\\P=45*0.01^2(0.99)^8=0.42$

b) We have, $1-(1-p)^n=P$ , Here P is the probability that at least one particle will penetrate the shield, this probabity has to be equal or greater than 0.95. Therefore, this will be equal to subtract from the total probability, the probability that the particles do not penetrate raised to the total number of particles.