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hoa [83]
3 years ago
11

Solve equation 4(k-6)-(3k +2)=-5

Mathematics
1 answer:
Alja [10]3 years ago
4 0
4 (k-6)-(3k+2)=-5
4k-24-3k-2=-5
k-26=-5
k=21
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Answer:

The answer is the option D

f(6)=g(6) and f(18)=g(18)

Step-by-step explanation:

we have

f\left(x\right)=\left|x-9\right|

g(x)=0.5x

we know that

The solution of the system of equations is the intersection point both graphs

Using a graphing tool

see the attached figure

The solution are the points (6,3) and (18,9)

therefore

The solution of the equation \left|x-9\right|=0.5x are

x=6, x=18

so

For x=6

f\left(6\right)=\left|6-9\right|=3

g(6)=0.5(6)=3

f(6)=g(6)

For x=18

f\left(18\right)=\left|18-9\right|=9

g(18)=0.5(18)=9

f(18)=g(18)

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3 years ago
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When you climb a rope , you change what energy into what energy
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Potential energy on the ground to kinetic energy climbing the rope to gravitational potential energy at the top of the rope
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Simplify (x + 2/ x^2 + 2x -3) / (x + 2/x^2 - x)
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Answer:

The simplest form is x/(x + 3)

Step-by-step explanation:

* To simplify the rational Expression lets revise the factorization

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*  To factor a quadratic in the form x² ± bx ± c:

- First look at the c term  

# If the c term is a positive number, and its factors are r and s they

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#  If the c term is a negative number, then either r or s will be negative

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- Second look at the b term.  

# If the c term is positive and the b term is positive, then both r and

  s are positive.  

Ex: x² + 5x + 6 = (x + 3)(x + 2)  

# If the c term is positive and the b term is negative, then both r and s

  are negative.  

Ex:  x² - 5x + 6 = (x -3)(x - 2)

# If the c term is negative and the b term is positive, then the factor

  that is positive will have the greater absolute value. That is, if

  |r| > |s|, then r is positive and s is negative.  

Ex: x² + 5x - 6 = (x + 6)(x - 1)

# If the c term is negative and the b term is negative, then the factor

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Ex: x² - 5x - 6 = (x - 6)(x + 1)

* Now lets solve the problem

- We have two fractions over each other

- Lets simplify the numerator

∵ The numerator is \frac{x+2}{x^{2}+2x-3}

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∵  The denominator = x² + 2x - 3

- The last term is negative then the two brackets have different signs

∵ 3 = 3 × 1

∵ 3 - 1 = 2

∵ The middle term is +ve

∴ -3 = 3 × -1 ⇒ the greatest is +ve

∴ x² + 2x - 3 = (x + 3)(x - 1)

∴ The numerator = \frac{(x+2)}{(x+3)(x-2)}

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∵ The denominator is \frac{x+2}{x^{2}-x}

- Factorize its denominator

∵  The denominator = x² - 2x

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∵ x² ÷ x = x

∵ -x ÷ x = -1

∴ x² - 2x = x(x - 1)

∴ The denominator = \frac{(x+2)}{x(x-1)}

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∴ The fraction = \frac{(x+2)}{(x+3)(x-1)}*\frac{x(x-1)}{(x+2)}

* Now we can cancel the bracket (x + 2) up with same bracket down

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∴ The simplest form = \frac{x}{x+3}

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1.8 or 9/5

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.................................

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