What are the period and amplitude of the function?
2 answers:
Answer:
The correct option is 3.
Step-by-step explanation:
The general form of a cosine function is
where, A is amplitude, 2π/B is period, C is phase sift and D is midline.
The amplitude of the function is 4.
The given graph complete a cycle in the interval [0,2π], therefore the period of the graph is 2π.
Therefore the correct option is 3.
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Hello!
The problem has asked that we write a point-slope equation of the line in the image above. Point-Slope Form uses the following formula:
y –
= m(x – 
)
In this case, M represents the slope while
and 
represent the corresponding X and Y values of any given point on the line.
We are given that the slope of the line is -
. We also know that any given point on a graph takes the form (x,y). Based on the single point provided in the image above, we can determine that 
is equal to 6 and 
is equal to 2. Now insert all known values into the point-slope formula above:
y – 2 = -(x – 6)
We have now successfully created an equation based on the information given in the problem above. Looking at the four possible options, we can now come to the conclusion that the answer is C.
I hope this helps!
The problem has asked that we write a point-slope equation of the line in the image above. Point-Slope Form uses the following formula:
y –
In this case, M represents the slope while
We are given that the slope of the line is -
y – 2 = -
We have now successfully created an equation based on the information given in the problem above. Looking at the four possible options, we can now come to the conclusion that the answer is C.
I hope this helps!
So a triangular prisim is like a triangle stacked on top of x number of identical triangles making a height, like a piece of paper made into a stack
so
basically find the area of each side and add
look at diagram/attachment
find area of triangle
1/2 b times h= area of 1 triangular face
multiply by 2 because 2 sides so 1/2 times 2 b times h=b times h
then 3 other sides
find area of each side and add
areas=(H times B)+(H times c)+(H times a)
so SA=(b times H)+(H times B)+(H times c)+(H times a)
so
basically find the area of each side and add
look at diagram/attachment
find area of triangle
1/2 b times h= area of 1 triangular face
multiply by 2 because 2 sides so 1/2 times 2 b times h=b times h
then 3 other sides
find area of each side and add
areas=(H times B)+(H times c)+(H times a)
so SA=(b times H)+(H times B)+(H times c)+(H times a)