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Vitek1552 [10]
2 years ago
9

What are the period and amplitude of the function?

Mathematics
2 answers:
jok3333 [9.3K]2 years ago
6 0

Answer:

The correct option is 3.

Step-by-step explanation:

The general form of a cosine function is

f(x)=A\cos (Bx+C)+D

where, A is amplitude, 2π/B is period, C is phase sift and D is midline.

A=midline=\frac{Maximum-Minimum}{2}

A=midline=\frac{4-(-4)}{2}

A=midline=4

The amplitude of the function is 4.

The given graph complete a cycle in the interval [0,2π], therefore the period of the graph is 2π.

Therefore the correct option is 3.

lianna [129]2 years ago
5 0

ANSWER

Period: 2π , amplitude: 4

EXPLANATION

The graphed function is

y =  4\cos(x)

The amplitude of this function is

|4|  = 4

The period is 2π because there is no phase shift hence the period is still equal to the parent function.

Period: 2π , amplitude: 4

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Answer:

there are approximately 5.035 months when there is less than 9 million square meters of sea ice around the North Pole in a year.

Step-by-step explanation:

Given the data in the question;

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Now, we use a cosine curve to model this scenario

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Now, the horizontal stretch factor will be;

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S(t) = 9

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so we have;

cos⁻¹( -1/4 ) = π/6 × (t₁-2)  -------- let this be equation 2

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we have'

t₁ - t₂ = 6/π × ( 2π - cos⁻¹( -1/4 ) - cos⁻¹( -1/4 ) )

t₁ - t₂ = 6/π × ( 2π - 2cos⁻¹( -1/4 )  

t₁ - t₂ = 6/π × ( π - cos⁻¹( -1/4 )  

t₁ - t₂ = 6/π × ( π - 104.4775 )

t₁ - t₂ = 6/π × ( π - 104.4775 )  

t₁ - t₂ = 5.035

therefore, there are approximately 5.035 months when there is less than 9 million square meters of sea ice around the North Pole in a year.

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