Answer:
Hence safely 9 watermelons can be placed in a single container.
Step-by-step explanation:
Given that the weight (in pounds) of ``medium-size'' watermelons is normally distributed with mean 15 and variance 4.
X = weight in pounds of medium size watermelons is N(15, 2)
Let the water melons stored be n
Then the sample of n has a mean of (15) and std error =
Capacity = 140
Hence we can say either 8 or 9
If n=9, we have weight = 15*9+1.96*2/3 = 136.40
Hence safely 9 watermelons can be placed in a single container.