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katovenus [111]
3 years ago
11

20 points :)

Chemistry
1 answer:
NNADVOKAT [17]3 years ago
8 0
I think the answer is C but I’m sorry if it’s incorrect i tried searching it up.
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Which of the following is the correct scientific notation for 0.000056?
svet-max [94.6K]
Hi,

0.000056 = 5.6 \times  {10}^{ - 5}

Hope this helps.
r3t40
7 0
3 years ago
Ag2S + Al(s) = Al2S3 + Ag(s) (unbalanced)
Dovator [93]

Answer:

1. 0.97 V

2. Al_(_s_)/Al^+^3~_(_a_q_)~//~Ag^+~_(_a_q_)/Ag_(_s_)

Explanation:

In this case, we can start with the <u>half-reactions</u>:

Ag^+~_(_a_q_)->~Ag_(_s_)

Al_(_s_)~->~Al^+^3~_(_a_q_)

With this in mind we can <u>add the electrons</u>:

Ag^+~_(_a_q_)+~e^-~->~Ag_(_s_)  <u>Reduction</u>

Al_(_s_)~->~Al^+^3~_(_a_q_)+~3e^-~ <u>Oxidation</u>

The reduction potential values for each half-reaction are:

Ag_2S~+~e^-~->~Ag_(_s_)~+~S^-^2~_(_a_q_) - 0.69 V

Al^+^3~_(_a_q_)+~2e^-~->~Al_(_s_) -1.66 V

In the aluminum half-reaction, we have an oxidation reaction, therefore we have to <u>flip</u> the reduction potential value:

Al_(_s_)~->~Al^+^3~+~2e^-~ +1.66 V

Finally, to calculate the overall potential we have to <u>add</u> the two values:

1.66 V - 0.69 V = <u>0.97 V</u>

For the second question, we have to keep in mind that in the cell notation we put the anode (the oxidation half-reaction) in the left and the cathode (the reduction half-reaction) in the right. Additionally, we have to use "//" for the salt bridge, therefore:

Al_(_s_)/Al^+^3~_(_a_q_)~//~Ag^+~_(_a_q_)/~Ag_(_s_)

I hope it helps!

3 0
3 years ago
Calculate the mass of Iron in 40g of Fe203​
Nat2105 [25]

Answer:

   ‏‏‎ ‎

Explanation:‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎

7 0
2 years ago
What is the specific heat of a substance if a mass of 10.0 kg increases in temperature from 10.0°C to 70.0°C when 2,520 J of hea
Ksju [112]

Answer:

A. 0.00420 J/(gi°C)

Explanation:

i got it rigt

8 0
2 years ago
What is the relative humidity of the air when the dry-bulb temperature is 4°C and the dewpoint is -4°C?
boyakko [2]

Answer:56%

Explanation:

In the dewpoint chart when you line it up it ends up at 56%

3 0
3 years ago
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