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zvonat [6]
1 year ago
14

Which chemical equations show an oxidation- reduction reaction

Chemistry
1 answer:
saveliy_v [14]1 year ago
4 0

Answer:

 O2 + 2H2 → 2H2O MgSO4 + CaCl2 → MgCl2 + CaSO4 2Al + 6HI → 2AlI3 + 3H2 FeCl2 + Na2CO3 → FeCO3 + 2NaCl 2AgNO3 + Na2S → Ag2S + 2NaNO3

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Identify the precipitation reactions. drag the appropriate items to their respective bins.
lana66690 [7]
I can't fully answer this question because it is incomplete. In order for me to help you, I could just define what a precipitation reaction is and give a concrete example.

A precipitation reaction consists of two aqueous solutions that when reacted together, forms an insoluble salt. For example, 

AgNO₃ (aq) + HCl (aq) --> AgCl (s) + HNO₃ (aq)

In this case, the precipitate is AgCl, Silver Chloride, which appears as a white solid.
7 0
2 years ago
Read 2 more answers
What could we use to measure the energy of particles when we are unable to see them
iVinArrow [24]

Answer:

Temperature.

Explanation:

Temperature is a measure of the average kinetic energy of a system.

6 0
3 years ago
Select which of the following are used to determine the age of the Earth. Select 3.
saveliy_v [14]

Meteorites discovered on earth

7 0
2 years ago
How could you tell whether a liquid is <br> honey or vinegar?
MissTica
Based on the liquids viscosity (which is a measure of how quickly/slowly a fluid can flow).

Higher viscosity represents a "thicker" liquid & slower flow (honey)
Lower viscosity represents a "thinner" liquid & quicker flow (vinegar)

4 0
3 years ago
Read 2 more answers
How many grams of NaOH needed to completely neutralize 3L of 1.75M HCL
Sedaia [141]

Answer:

209.98 g of NaOH

Explanation:

We are given;

  • Volume of HCl as 3 L
  • Molarity of HCl as 1.75 M

We are required to calculate the mass of NaOH required to completely neutralize the acid given.

First, we write a  balanced equation for the reaction between NaOH and HCl

That is;

NaOH + HCl → NaCl + H₂O

Second, we determine the number of moles of HCl

Number of moles = Molarity × Volume

                             = 1.75 M × 3 L

                             = 5.25 moles

Third, we use the mole ratio to determine the moles of NaOH

From the reaction,

1 mole of NaOH reacts with 1 mole of HCl

Therefore;

Moles of NaOH = Moles of HCl

                          = 5.25 moles

Fourth, we determine the mass of NaOH

Molar mass of NaOH = 39.997 g/mol

Mass of NaOH = 5.25 moles × 39.997 g/mol

                        = 209.98 g

Thus, 209.98 g of NaOH will completely neutralize 3L of 1.74 M HCl

6 0
3 years ago
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