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zvonat [6]
2 years ago
14

Which chemical equations show an oxidation- reduction reaction

Chemistry
1 answer:
saveliy_v [14]2 years ago
4 0

Answer:

 O2 + 2H2 → 2H2O MgSO4 + CaCl2 → MgCl2 + CaSO4 2Al + 6HI → 2AlI3 + 3H2 FeCl2 + Na2CO3 → FeCO3 + 2NaCl 2AgNO3 + Na2S → Ag2S + 2NaNO3

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How can you raise the average kinetic energy of the water molecules in a glass of water?
Crazy boy [7]
Boil it. Kinetic energy is energy of motion and hot water moleculues move more
8 0
3 years ago
Phase change is based on the_________, which states that phase change occurs with changing average kinetic energy. a. Law of con
AleksAgata [21]

Answer:

d but I'm not sure.............

8 0
3 years ago
Which material is the lest likely to be recognized as a mixture by looking at it under a microscope ?
Lisa [10]
Hello,

The answer is option C <span>homogeneous mixture.

Reason:

The answer is option C because you can find </span><span>homogeneous mixtures anywhere for example: Vinegar. Its not option A because suspension is usually in elements but as not a mixture. Its not option B because a colloid is a measurement tool that allows to make compounds (mixtures).Its also not option D because those type o mixtures are hard to find in extreme weather conditions.

If you need anymore help feel free to ask me!

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4 0
3 years ago
Read 2 more answers
How many protons, electrons, and neutrons does an atom with atomic number
sergey [27]

Answer:

protons : 10

electron : 10

neutron : 10

Explanation:

Protons will usually be the same as the electrons when its a <u>Atom</u> (when its a ion or covalent bond or simple bond they will most likely be different)

the atomic number represents protons and electrons

the mass number - the atomic number = neutron

8 0
3 years ago
Yet a third pair of compounds of manganese and oxygen is 50.48% and 36.81% oxygen respectively. In what small whole number ratio
Mariulka [41]

Answer:

The number ratio is 4:7

Explanation:

Step 1: Data given

Compound 1 has 50.48 % oxygen

Compound 2 has 36.81 % oxygen

Molar mass oxygen = 16 g/mol

Molar mass manganese = 54.94 g/mol

Step 2: Calculate % manganes

Compound 1: 100 - 50.48 = 49.52 %

Compound 2: 100 - 36.81 = 63.19 %

Step 3: Calculate mass

Suppose mass of compounds = 100 grams

Compound 1:

 50.48 % O = 50.48 grams

 49.52 % Mn = 49.52 grams

Compound 2:

36.81 % O = 36.81 grams

63.19 % Mn = 63.19 grams

Step 4: Calculate moles

Compound 1

Moles O = 50.48 grams / 16.0 g/mol = 3.155 moles

Moles Mn = 49.52 grams / 54.94 g/mol = 0.9013 moles

Compound 2

Moles O = 36.81 grams / 16.0 g/mol = 2.301 moles

Moles Mn = 63.19 grams / 54.94 g/mol = 1.150 moles

Step 5: calculate mol ratio

We will divide by the smallest amount of moles

Compound 1

O: 3.155/0.9013 = 3.5

Mn: 0.9013 / 0.9013 = 1

Mn2O7

Compound 2

O: 2.301 / 1.150 = 2

Mn: 1.150 / 1.150 = 1

MnO2

The number ratio is 2:3.5 or 4:7

7 0
3 years ago
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