1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ioda
3 years ago
9

What product(s) would be formed when these are the reactants? C5H12 + O2 (limited)

Chemistry
1 answer:
damaskus [11]3 years ago
7 0

Answer:

Carbon dioxide and water I believe because it is a combustion reaction

You might be interested in
Number of molecules of baking soda
Softa [21]

Answer:

Baking soda = No. of atoms are 1 sodium + 1 Hydrogen + 1 carbon + 3 oxygens = 6 atoms per molecule.

8 0
3 years ago
Read 2 more answers
How does a molecule differ from an atom?
Eddi Din [679]

Answer:

According to my research A molecule is two or more atoms held together by covalent bonds. An atom is the smallest part of an element. ... A sodium atom has one outer electron, and a carbon atom has four outer electrons.

Explanation:

5 0
3 years ago
What is the name of SnF2
Inessa [10]

Answer:

Tin (II) Fluoride......

7 0
3 years ago
Two students are working together to build two models. Both models will represent the molecular structure of sodium bicarbonate,
vfiekz [6]

Answer:

Altogether for both models; two red jellybeans, two white jellybeans, two black jellybeans and six blue jellybeans.

<em>Note: Since no specific color was stated for oxygen atoms, the answer assigns blue colored jellybeans to represent oxygen atoms.J</em>

Explanation:

Sodium bicarbonate, NaHCO₃ is a compound composed of one atom of sodium, one atom of hydrogen, one atom of carbon and three atoms of oxygen.

Since red jellybeans represent sodium atoms, white jellybeans represent hydrogen atoms, black jellybeans represent carbon atoms and blue jellybeans represent oxygen atoms, each of the two students will require the following number of each jellybean for their model of sodium carbonate: One red jellybean, one white jellybean, one black jellybean and three blue jellybeans.

Altogether for both models; two red jellybeans, two white jellybeans, two black jellybeans and six blue jellybeans.

8 0
3 years ago
Determine the resulting pH when 12mL if 0.16M HCl are reacted with 32 mL if 0.24M KOH.
TEA [102]

Answer:

pH = 13.1

Explanation:

Hello there!

In this case, according to the given information, we can set up the following equation:

HCl+KOH\rightarrow KCl+H_2O

Thus, since there is 1:1 mole ratio of HCl to KOH, we can find the reacting moles as follows:

n_{HCl}=0.012L*0.16mol/L=0.00192mol\\\\n_{KOH}=0.032L*0.24mol/L=0.00768mol

Thus, since there are less moles of HCl, we calculate the remaining moles of KOH as follows:

n_{KOH}=0.00768mol-0.00192mol=0.00576mol

And the resulting concentration of KOH and OH ions as this is a strong base:

[KOH]=[OH^-]=\frac{0.00576mol}{0.012L+0.032L}=0.131M

And the resulting pH is:

pH=14+log(0.131)\\\\pH=13.1

Regards!

3 0
3 years ago
Other questions:
  • 1. Lani conducted an experiment in which she tested the reactivity of a substance. She placed two
    8·1 answer
  • Match each process to where it occurs in the carbon cycle
    5·1 answer
  • If I have 15.40mL of 1.4M HBr(aq) and add 22.10mL KOH what is the molarity of<br>KOH being used?​
    12·1 answer
  • The part of the atom that accounts for electricity is the
    15·1 answer
  • Which statement describes the valence electrons in metallic bonds? a)They are shared equally between two atoms. b)They are share
    7·2 answers
  • Jordan places a hot spoon into a container of ice
    14·1 answer
  • The mass of the electron is..
    15·2 answers
  • How can a Hydrogen atom turn into a<br> Hydrogen ion (H+)?
    12·1 answer
  • Which image represents ether? Check all that apply.
    9·1 answer
  • Compare the relative strength of the two forces B and C. Explain how you determined this comparison by identifying the forces.
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!