Answer:
Step-by-step explanation:
We have been given that an arrow is shot straight up from a cliff 58.8 meters above the ground with an initial velocity of 49 meters per second. Let up be the positive direction. Because gravity is the force pulling the arrow down, the initial acceleration of the arrow is −9.8 meters per second squared.
We know that equation of an object's height t seconds after the launch is in form 
, where
g = Force of gravity,
= Initial velocity,
= Initial height.
For our given scenario 
, 
and 
. Upon substituting these values in object's height function, we will get:
Therefore, the function for the height of the arrow would be .
Answer:
Step-by-step explanation:
(x-1)²+(y-2)² =4 compare the given equation with the general one
(x-h)² +(y-k)² =r², where (h, k) are coordinates of the center and r is radius
so center is at ( 1, 2) and radius is 2
Answer:
A.non at all so, please choose the right answer
Answer:
c
Step-by-step explanation:
I don't trust myself so I am sorry if it is wrong
Answer:
The solution is (-2/3,7/3)
Step-by-step explanation:
1) What is the bottom part saying? I will just solve what I see on top since that may be the only part you need to solve, comment what the bottom part is if you need it, I'll help.
2) y=7/3 by solving. for y.
3) x = -4/6 by solving for x after plugging in the y.
4) Your answer is (-2/3,7/3).
