Solve the equation and check your solution. (If there is no solution, enter NO SOLUTION.) (4x − 6) divided by (4x+3) = 2/3

Click photo needing help ASAP! Please

Murljashka [212]

Answer:

$\huge\boxed{y=6x+9}$

Step-by-step explanation:

In order to put this equation into slope-intercept form, we want to get this into the form $y=mx+b$ , where m is the slope (coefficient) and b is the y-intercept.

We already have the equation $y-6x=9$ . Looking at this equation, we can see that we have to get 6x off the left side of the equation and on to the right.

To do this, we can add 6x to both sides. However, if we add 6x to one side we must add it to the other.

So, let’s add 6x to both sides.

$y -6x + 6x = 9 + 6x$

$y = 9 + 6x$

We can now rearrange the terms.

$y = 6x+9$

Hope this helped!

6 0

4 years ago

Here is an inequality -10+x÷4+5>7x-5÷3

Flura [38]

Answer:

here is the answer x>1/2

7 0

3 years ago

Use the quadratic equation 2? + 10x + 28 = 4 to complete the following statements.

MaRussiya [10]

Answer:

You’d brainless

Step-by-step explanation:

7 0

3 years ago

PLEASE HELP!!!!

Lunna [17]

NOTES:

Given a quadratic function in standard format (y = ax² + bx + c), the direction of the parabola is as follows:

if "a" is positive, then opens UP
if "a" is negative, then opens DOWN

Given a quadratic function in standard format (y = ax² + bx + c), the vertex can be found as follows:

the Axis Of Symmetry (x-value) is: x = $\frac{-b}{2a}$
y-value is found by plugging in the AOS for "x" in the equation

****************************************************************************************

1) y = x² + 11x + 24

a = +1 so the parabola opens UP

x = $\frac{-b}{2a}$ = $\frac{-11}{2(1)}$ = $-\frac{11}{2}$

y = $(-\frac{11}{2})^{2}$ + 11 $(-\frac{11}{2} )$ + 24 = $-\frac{25}{4}$

vertex $(-\frac{11}{2}$ , $-\frac{25}{4})$ is in Quadrant 3 and is below the x-axis

This COULD be the graph of the rain gauge.

The graph should contain the vertex, x-intercepts (-3, 0) and (-8, 0), and y-intercept (0, 24)

******************************************************************************************

2) y = -x² - 6x - 8

a = -1 so the parabola opens DOWN

x = $\frac{-b}{2a}$ = $\frac{-(-6)}{2(-1)}$ = $\frac{6}{-2}$ = -3

y = -(-3)² - 6(-3) - 8 = -9 + 18 - 8 = 1

vertex (-3, 1) is in Quadrant 2 and is above the x-axis

This could NOT be the graph of the rain gauge.

The graph should contain the vertex, x-intercepts (-2, 0) and (-4, 0), and y-intercept (0, -8)

******************************************************************************************

3) y = x² - 2x + 3

a = 1 so the parabola opens UP

x = $\frac{-b}{2a}$ = $\frac{-(-2)}{2(1)}$ = $\frac{2}{2}$ = 1

y = (1)² - 2(1) + 3 = 1 - 2 + 3 = 2

vertex (1, 2) is in Quadrant 1 and is above the x-axis

This could NOT be the graph of the rain gauge.

The graph should contain the vertex, y-intercept (0, 3), and its mirror image (2, 3). There are no x-intercepts

******************************************************************************************

4) y = x² + 4x + 4

a = 1 so the parabola opens UP

x = $\frac{-b}{2a}$ = $\frac{-4}{2(1)}$ = -2

y = (-2)² + 4(-2) + 4 = 4 - 8 + 4 = 0

vertex (-2, 0) is in Quadrant 2 and is on the x-axis

This COULD be the graph of the rain gauge.

The graph should contain the vertex, y-intercept (0, 4), and its mirror image (-4, 4). The x-intercept is the vertex.

Compared to the other four graphs, this is most likely the equation for the rain gauge!

******************************************************************************************

5) y = 3x² + 21x + 30

a = +3 so the parabola opens UP

x = $\frac{-b}{2a}$ = $\frac{-21}{2(3)}$ = $-\frac{7}{2}$

y = 3 $(-\frac{7}{2})^{2}$ + 21 $(-\frac{7}{2} )$ + 30 = $-\frac{27}{4}$

vertex $(-\frac{7}{2}$ , $-\frac{27}{4})$ is in Quadrant 3 and is below the x-axis

This COULD be the graph of the rain gauge.

The graph should contain the vertex, x-intercepts (-2, 0) and (-5, 0), and y-intercept (0, 30)

*******************************************************************************************

4 0

4 years ago

Read 2 more answers

LeRon draws an orange counter from one bag and a red counter from another bag. Which statement is true?

Gelneren [198K]

Hello there!

The question asks if the events are independent or dependent.
Well, let's establish what an independent and dependent event is.

An independent event is an occurrence in which two or more events do not have effect on each other, regardless what happens during each scenario.

An independent event would be (for example) "I flipped a coin and rolled a dice." Both of these are independent events, as they do not have any effect on eachother.

A dependent event is an occurrence in which two or more events have effects on eachother. For example "I pull a red card out of a deck of cards. I then pull a black card out of the same deck."

The question you have is:
LeRon draws an orange counter from one bag and a red counter from another bag. Are the events dependent or independent?

Since that LeRon draws two different counters from two separate bags, the events do not effect each other, thus making the events independent.

I hope this helps!

5 0

3 years ago