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ANEK [815]
4 years ago
10

Write an equation of the line that passes through the points (2, -1) and (2, 5). Show all work

Mathematics
1 answer:
Westkost [7]4 years ago
7 0

Answer:

x = 2

Step-by-step explanation:

The 2 coordinate points have the same x- coordinate of 2

This indicates that the line passing through them is vertical with equation

x = c

Where c is the value of the x- coordinates the line passes through, thus

x = 2 ← equation of line

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Express the number 68,708 in word form and expanded form.<br><br> Word form ?<br> Expanded form ?
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Sixty eight thousand seven hundred and eight in word form

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9x -1 = 80<br> A -10<br> B 9<br> C 10<br> D -9
Fittoniya [83]

Answer:

The answer is B!

Step-by-step explanation:

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3 years ago
32​% of college students say they use credit cards because of the rewards program. You randomly select 10 college students and a
Tems11 [23]

Answer:

a) P(X=2)=(10C2)(0.32)^2 (1-0.32)^{10-2}=0.211

b) P(X> 2)=1-P(X\leq 2)=1-[0.0211+0.0995+0.211]=0.668

c) P(2 \leq x \leq 5)=0.211+0.264+0.218+0.123=0.816

Step-by-step explanation:

1) Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

2) Solution to the problem

Let X the random variable of interest, on this case we now that:

X \sim Binom(n=10, p=0.32)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

Part a

P(X=2)=(10C2)(0.32)^2 (1-0.32)^{10-2}=0.211

Part b

P(X> 2)=1-P(X\leq 2)=1-[P(X=0)+P(X=1)+P(X=2)]

P(X=0)=(10C0)(0.32)^0 (1-0.32)^{10-0}=0.0211  

P(X=1)=(10C1)(0.32)^1 (1-0.32)^{10-1}=0.0995

P(X=2)=(10C2)(0.32)^2 (1-0.32)^{10-2}=0.211

P(X> 2)=1-P(X\leq 2)=1-[0.0211+0.0995+0.211]=0.668

Part c

P(2 \leq x \leq 5)=P(X=2)+P(X=3)+P(X=4)+P(X=5)

P(X=2)=(10C2)(0.32)^2 (1-0.32)^{10-2}=0.211

P(X=3)=(10C3)(0.32)^3 (1-0.32)^{10-3}=0.264

P(X=4)=(10C4)(0.32)^4 (1-0.32)^{10-4}=0.218

P(X=5)=(10C5)(0.32)^5 (1-0.32)^{10-5}=0.123

P(2 \leq x \leq 5)=0.211+0.264+0.218+0.123=0.816

6 0
3 years ago
Hello, happy Friday, I am just here with some geometry questions.
klasskru [66]

Answer:

  • U'(-14, 8)

Step-by-step explanation:

<u>The transformations include:</u>

  • T<-2,2>·D3

This is a dilation by a scale factor of 3 and then translation 2 units left and 2 units up.

<u>The transformation applied to the point U:</u>

  • U(-4,2) → U'(-4*3 - 2, 2*3 + 2) = U'(-14, 8)
4 0
3 years ago
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