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den301095 [7]
3 years ago
11

Divide 30 in the ratio of 2 : 4

Mathematics
1 answer:
cricket20 [7]3 years ago
8 0
60 because 2:4 is 1/2, and when you divide by a fraction, you multiply by the reciprocal (2/1 instead of 1/2) which would be 60 in this case.
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Find the slope of the line passing through the points (5,7) and (-4,2).
Andre45 [30]

Your answer is A!

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Prove that x-s-t is a factor of x^3 - s^3 -t^3 -3st(s+t)
inessss [21]
1. Introduction. This paper discusses a special form of positive dependence. Positive dependence may refer to two random variables that have a positive covariance, but other definitions of positive dependence have been proposed as well; see [24] for an overview. Random variables X = (X1, . . . , Xd) are said to be associated if cov{f(X), g(X)} ≥ 0 for any two non-decreasing functions f and g for which E|f(X)|, E|g(X)|, and E|f(X)g(X)| all exist [13]. This notion has important applications in probability theory and statistical physics; see, for example, [28, 29]. However, association may be difficult to verify in a specific context. The celebrated FKG theorem, formulated by Fortuin, Kasteleyn, and Ginibre in [14], introduces an alternative notion and establishes that X are associated if ∗ SF was supported in part by an NSERC Discovery Research Grant, KS by grant #FA9550-12-1-0392 from the U.S. Air Force Office of Scientific Research (AFOSR) and the Defense Advanced Research Projects Agency (DARPA), CU by the Austrian Science Fund (FWF) Y 903-N35, and PZ by the European Union Seventh Framework Programme PIOF-GA-2011-300975. MSC 2010 subject classifications: Primary 60E15, 62H99; secondary 15B48 Keywords and phrases: Association, concentration graph, conditional Gaussian distribution, faithfulness, graphical models, log-linear interactions, Markov property, positive
8 0
3 years ago
Work out the circumference of this circle.<br> Give your answer in terms of 3.142<br> r=6 mm
soldi70 [24.7K]

Answer:

C≈37.7

Step-by-step explanation:

C=2πr=2·π·6≈37.69911

<h3><em>i rounded</em></h3><h3><em /></h3>
6 0
3 years ago
An isosceles triangle has an area of 254 km², and the angle between the two equal sides is 53°. Find the length of the two equal
torisob [31]
Area of a triangle = 1/2 ab sinC

In this equation the angle C is between the two adjacent sides ab
Since the lengths are equal we can call them both X
Hence 254= 1/2 (x)(x) sin53
By simplifying 508 = (x^2) sin53
So therefore x is the square root of 508 divided by sin53 which means the length of the sides is 35.8km to 3 significant figures
8 0
3 years ago
If the mean weight of 4 backfield members on the football team is 221 lb and the mean weight of the 7 other players is 202 lb, w
MatroZZZ [7]

Let x_1, x_2, x_3, x_4, x_5, x_6, x_7, x_8, x_9, x_{10}, x_{11} be the weight of i-th player.

1. If the mean weight of 4 backfield members on the football team is 221 lb, then

\dfrac{x_1+x_2+x_3+x_4}{4}=221\ lb.

2. If the mean weight of the 7 other players is 202 lb, then

\dfrac{x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}}{7}=202\ lb.

3. From the previous statements you have that

x_1+x_2+x_3+x_4=221\cdot 4=884 \lb,\\ \\x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}=202\cdot 7=1414\ lb.

Add these two equalities and then divide by 11:

x_1+x_2+x_3+x_4+x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}=884+1414=2298\ lb,\\ \\\dfrac{x_1+x_2+x_3+x_4+x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}}{11}=\dfrac{2298}{11}=208\dfrac{10}{11}\ lb.

Answer: the mean weight of the 11-person team is 208\dfrac{10}{11}\ lb.

4 0
3 years ago
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