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VladimirAG [237]

3 years ago

5

Question # 5 what is the sum?

1 answer:

Blizzard [7]3 years ago

8 0

Answer: C) d+13/d+4

Here’s why:

Step 1: Rewrite the factor
d^2 + 7d +4d +28 / (d+4)^2 + 6 / d+4

Step 2 : factor out d from the expression and factor out 4 from the expression
d × (d+7) + 4(d+7) / (d+4) ^2 + 6 / d+4

Step 3: Factor out d+7 from the expression
(d+7) × (d+4) / (d+4) ^2 + 6 / d+4

Step 4: simply the expression
d+7 / d+4 + 6/ d+4

Step 5: write all numerators above the common denominator
d+7+6 / d+4

Step 6: add the numbers and you get
d+13 / d+4

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Which pair of functions have the same domain? A. F(x)= sin x and g(x) = tan x B. F(x) = cos x and f(x) = csc x C. G(x) = tan x a

EastWind [94]

Answer:

The correct choice is D

Step-by-step explanation:

The trigonometric functions, $\sin x$ and $\cos x$ are defined for all real numbers.

$\tan x=\frac{\sin x}{\cos (x)}$ , this function is not defined where $\cos x=0$ .

$\cot x=\frac{\cos x}{\sin (x)}$ , this function is not defined where $\sin x=0$ .

$\csc x=\frac{1}{\sin (x)}$ , this function is not defined where $\sin x=0$ .

For option A

The domain of $f(x)=\sin(x)$ is all real numbers.

The domain of g(x) =tanx is $x\ne \frac{(2n+1)\pi}{2}$

For option B

The domain of $f(x)=\cos(x)$ is all real numbers.

The domain of f(x) =csc(x) is $x\ne n\pi$

For option C,

The domain of G(x) =tanx is $x\ne \frac{(2n+1)\pi}{2}$

The domain of f(x) =cot(x) is $x\ne n\pi$

For option D;

The domain of f(x) =cot(x) is $x\ne n\pi$

The domain of f(x) =csc(x) is $x\ne n\pi$

3 0

3 years ago

Read 2 more answers

PLZZZZZZ answer these questions

Daniel [21]

Answer:

for the last question, there is a slope calculator on the internet that could help with that

6 0

2 years ago

Jeff purchased 5 items at the same price and 1 item for $2.95. What was the individual price of the 5 items if Jeff's total was

Soloha48 [4]

The answer is A. 3.19, all you have to do it multiply 3.19x5 then add the 2.95 hope this helps

7 0

3 years ago

If UV = 6 and TV = 12, what is TU?

love history [14]

Answer:

TU = 6

Step-by-step explanation:

Using the Segment Addition Postulate, we know that TU + UV = TV, and since UV = 6 and TV = 12, we know that TU + 6 = 12, therefore, TU = 6.

3 0

3 years ago

Can someone please help me ASAP

Sonja [21]

Answer:

x^2 + 5n = 4mx

=> x^2 - 4mx + 5n = 0

D=0 (since one root then roots are equal)

b^2-4ac = 0

(-4m)^2 - 4(1)(5n) = 0

16m^2 - 20n = 0

16m^2 = 20n

8m^2 = 10n

4m^2 = 5n

hope it helps.......

7 0

3 years ago