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3 years ago

49.Which of the following statements regarding chemical equilibrium is true?

2 answers:

8 0

Answer : The correct statement is, (b) A system at equilibrium maintains the concentrations of all reactants/products over time.

Explanation :

Equilibrium reaction : It is a reaction which do not go on completion that means the reactant forms product and the products goes back to the reactants simultaneously.

In a chemical equilibrium reaction, the equilibrium state is achieved when the rate of forward reaction becomes equals to the rate of the backward reaction.

Equilibrium state is the state when the reactants and products are present but the concentrations does not change with time that means there is no changes in the concentration the products and reactants.

Equilibrium is shown with a way arrow like, $(\rightleftharpoons)$

A system does not stop at equilibrium.

Hence, the correct statement is, (b)

e-lub [12.9K]3 years ago

7 0

I think is Gonna be C

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Consider the reaction of ruthenium(III) iodide with carbon dioxide and silver. RuI3 (s) 5CO (g) 3Ag (s) Ru(CO)5 (s) 3AgI (s) Det

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71.6 g of Ru(CO)₅ is the maximum mass that can be formed.

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RuI₃ (s) + 5CO (g) + 3Ag (s) → Ru(CO)₅ (s) + 3AgI (s)

Firstly we determine the moles of each reactant:

169 g . 1mol /481.77g = 0.351 moles of RuI₃

58g . 1mol /28g = 2.07 moles of CO

96.2g . 1mol/ 107.87g = 0.892 moles

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3 moles of Ag react to 1 mol of RuI₃

Then 0.892 moles of Ag may react to (0.892 . 1) /3 = 0.297 moles

We have 0.351 moles of iodide and we need 0.297 moles, so this is an excess. In conclussion, Silver (Ag) is the limiting.

1 mol of RuI₃ react to 3 moles of Ag

Then, 0.351 moles of RuI₃ may react to (0.351 . 3) /1 = 1.053 moles

It's ok, because we do not have enough Ag. We only have 0.892 moles and we need 1.053.

5 moles of CO react to 3 moles of Ag

Then, 2.07 moles of CO may react to (2.07 . 3) /5 = 1.242 moles of Ag.

This calculate confirms the theory.

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3 moles of of Ag can produce 1 mol of Ru(CO)₅

Then 0.892 moles may produce (0.892 . 1) /3 = 0.297 moles

We convert moles to mass → 0.297 mol . 241.07g /mol = 71.6 g

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