Water can be returned to the atmosphere by a process known as

n a laboratory experiment, John uses a mesh to separate soil particles from water. Which technique of separation is he using?

Klio2033 [76]

He is using the filtration method.
It’s a technique which is used for separation of solids and fluids by putting them through a medium which allows only fluid to pass through, leaving the solids (in this case the soil) alone.
The fluid that passed is called the filtrate.

7 0

4 years ago

Given the following reaction:

babunello [35]

Answer:

1234.0

Explanation:

7 0

3 years ago

Which of the following is a physical property of a substance?? A. Combustion B. Corrosion C. Tendency to tarnish D. Solubility

Fofino [41]

A physical property does not change the substance.

Solubility would be the answer since all of the rest are changing the substance. They all deal with bonds except solubility.

Answer: D. Solubility

6 0

3 years ago

Read 2 more answers

Consider the balanced equation for the following reaction:

Zanzabum

<u>Answer:</u> The amount of carbon dioxide formed in the reaction is 5.663 grams

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

Given mass of oxygen gas = 8 g

Molar mass of oxygen gas = 32 g/mol

Putting values in equation 1, we get:

$\text{Moles of oxygen gas}=\frac{8g}{32g/mol}=0.25mol$

For the given chemical equation:

$7O_2(g)+2C_2H_6(g)\rightarrow 4CO_2(g)+6H_2O(l)$

By Stoichiometry of the reaction:

7 moles of oxygen gas produces 4 moles of carbon dioxide

So, 0.25 moles of oxygen gas will produce = $\frac{4}{7}\times 0.25=0.143mol$ of carbon dioxide

Now, calculating the mass of carbon dioxide from equation 1, we get:

Molar mass of carbon dioxide = 44 g/mol

Moles of carbon dioxide = 0.143 moles

Putting values in equation 1, we get:

$0.143mol=\frac{\text{Mass of carbon dioxide}}{44g/mol}\\\\\text{Mass of carbon dioxide}=(0.143mol\times 44g/mol)=6.292g$

To calculate the experimental yield of carbon dioxide, we use the equation:

$\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100$

Percentage yield of carbon dioxide = 90 %

Theoretical yield of carbon dioxide = 6.292 g

Putting values in above equation, we get:

$90=\frac{\text{Experimental yield of carbon dioxide}}{6.292g}\times 100\\\\\text{Experimental yield of carbon dioxide}=\frac{90\times 6.292}{100}=5.663g$

Hence, the amount of carbon dioxide formed in the reaction is 5.663 grams

7 0

3 years ago

How does the mass of an oxygen nucleus

nataly862011 [7]

Answer: The mass of the nucleus is less than the mass of the 8 protons and 8 neutrons.

Explanation:

5 0

3 years ago