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kow [346]
3 years ago
10

A 0.100-l sample of an unknown hno3 solution required 32.9 ml of 0.200 m ba(oh)2 for complete neutralization. what was the conce

ntration of the hno3 solution?
Chemistry
2 answers:
ddd [48]3 years ago
7 0
The reaction between HNO3 and Ba(OH)2 is given by the equation below;
2HNO3 + Ba(OH)2 = Ba(NO3)2 + 2H2O
Moles of Barium hydroxide used;
 = 0.200 × 0.039 l
 = 0.0078 Moles
The mole ratio of HNO3 and Ba(OH)2 is 2: 1
Therefore; moles of nitric acid used will be;
= 0.0078 ×2 = 0.0156 moles
But; 0.0156 moles are equal to a volume of 0.10
The concentration of Nitric acid will be; 
 =  (0.0156 × 1)/0.1 
 = 0.156 M
jok3333 [9.3K]3 years ago
4 0

Answer: 0.132 M

Explanation:

According to the neutralization law,

n_1M_1V_1=n_2M_2V_2

where,

M_1 = molarity of HNO_3 solution = ?

V_1 = volume of HNO_3 solution = 0.100 L = 100 ml (1L=1000ml)

M_2 = molarity of Ba(OH)_2 solution = 0.200 M

V_2 = volume of Ba(OH)_2 solution = 32.9 ml

n_1 = valency of HNO_3 = 1

n_2 = valency of Ba(OH)_2 = 2

1\times M_1\times 100=2\times 0.200\times 32.9

M_1=0.132

Therefore, the concentration of HNO_3 solution is 0.132 M

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Answer the following questions based on the reaction below: NaOH(aq) + KHP(s) --> NaKP(aq)+H2O(I)
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Answer:

<u />

  • <u>a) 1.44g</u>

<u />

  • <u>b) 77.3%</u>

<u />

Explanation:

<u>1. Chemical balanced equation (given)</u>

       NaOH(aq)+ KHP(s)\rightarrow NaKP(aq)+H_2O(l)

<u>2. Mole ratio</u>

1molNaOH(aq):1molKHP(s)

This is, 1 mol of NaOH will reacts with 1 mol of KHP.

<u />

<u>3. Find the number of moles in 72.14 mL of the base</u>

    Molarity=\text{number of moles of solute}/\text{volume of solution in liters}

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     \text{Number of moles of NaOH}=0.0978M\times 0.07214liter=0.007055mol

<u>4. Find the number of grams of KHP that reacted</u>

The number of moles of KHP that reacted is equal to the number of moles of NaOH, 0.007055 mol

Convert moles to grams:

  • mass = number moles × molar mass = 0.007055mol × 204.23g/mol
  • mass = 1.4408 g.

You have to round to 3 significant figures: 1.44 g (because the molarity is given with 3 significant figures).

<u>5. Find the percentage of KHP in the sample</u>

The percentage is how much of the substance is in 100 parts of the sample.

The formula is:

  • % = (mass of substance / mass of sample) × 100

  • % = (1.4408g/ 1.864g) × 100 = 77.3%
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