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The revenue will be 12,000 when the price of the product is $100
Given :
The monthly revenue of a certain company

We need to find out p when <u>Revenue R is 12000</u>
Lets replace R with 12000 and solve for p

Apply <em>quadratic formula </em>

Given that price must be greater than 50
So the revenue will be 12000 when the price of the product is $100
Learn more : brainly.com/question/21503855
Answer:
the constant of 6y+3 is 6y+3