Multiple 16 by 1 and then divide by 8 which makes 2.
Multiply 36 by 1 and then divide by 9 which makes 4.
The number of tests that it would take for the probability of committing at least one type I error to be at least 0.7 is 118 .
In the question ,
it is given that ,
the probability of committing at least , type I error is = 0.7
we have to find the number of tests ,
let the number of test be n ,
the above mentioned situation can be written as
1 - P(no type I error is committed) ≥ P(at least type I error is committed)
which is written as ,
1 - (1 - 0.01)ⁿ ≥ 0.7
-(0.99)ⁿ ≥ 0.7 - 1
(0.99)ⁿ ≤ 0.3
On further simplification ,
we get ,
n ≈ 118 .
Therefore , the number of tests are 118 .
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Answer: 9-2 & -2-(-9)
Correct me if I'm wrong.
Step-by-step explanation:
Answer:
X=3, y=5
Step-by-step explanation:
3x + y = 14 equation 1
y=5 equation 2
3x + 5 = 14. substitute value of y from equation 2 into equation 1
3x=9
x-3
-15 - (-3) + 6
-15 - (-3) = -15 + 3 = 3 - 15 = - 12
-12 + 6 = 6 - 12 = -6
Your answer is -6
