The two gears are shown n the diagram below.
ω₁ and ω₂ are the angular velocities of the larger and smaller gears respectively.
Part 1.
When the smaller gear makes one revolution, it turns through an angle of 2π radians or 360°.
Because the gears do not slip, the larger gear turns through an angle of θ, so that
(θ radians)*(8 in) = (2π radians)*(2 in)
or
8θ = 4π
θ = π/2 radians = 90°
Answer: 90.0°
Part 2.
When the larger gear makes one revolution, it turns through an angle of 2π radians.
Because the gears do not slip, the smaller gear turns through an angle φ, such that
(2 in)*(φ radians) = (8 in)*(2π radians)
or
2φ = 16π
φ = 8π radians
= (8π radians)*(1/2π rotations/radian)
= 4 rotations
Answer: 4 rotations
Answer: The method of solving "by substitution" works by solving one of the equations (you choose which one) for one of the variables (you choose which one), and then plugging this back into the other equation, "substituting" for the chosen variable and solving for the other. Then you back-solve for the first variable.
Step-by-step explanation:
Answer:
The rate of the boat in still water is 40 miles per hour
The rate of the current is 10 miles per hour
Step-by-step explanation:
we know that
The speed or rate is equal to divide the distance by the time
Let
x ----> the rate of the current (miles per hour)
y ----> the rate of the boat in still water (miles per hour)
we have that
<em>going upstream </em>
----> equation A
<em>going downstream </em>
----> equation B
Solve the system of equations by elimination
Adds equation A and equation B
<em>Find the value of x </em>
therefore
The rate of the boat in still water is 40 miles per hour
The rate of the current is 10 miles per hour
That is correct?
Dunno what the question is.