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enyata [817]
4 years ago
15

The radius of the circle traced out by the second hand on a clock is 6.00 cm. In a time t the tip of the second hand moves throu

gh an arc length of 19.0 cm. Determine the value of t in seconds.
Physics
1 answer:
quester [9]4 years ago
5 0

Answer:

30.29 s

Explanation:

We are given that

Radius=r=6 cm

Length of an arc=l=19 cm

We have to find the value of t in seconds.

\theta=\frac{l}{r}

Substitute the values then we get

\theta=\frac{19}{6}=3.17 rad

We know that

1 minute=60 seconds

In 60 seconds ,second hand makes an angle=2\piradian

2\pi radian made by second had in 60 sec.

1 radian made by second hand in \frac{60}{2\pi} sec

3.17 rad made by second hand in \frac{60}{2\pi}\times 3.17=\frac{60}{2\times 3.14}\times 3.17=30.29 s

Hence, the value of t =30.29 s

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3 years ago
What are the si units for average speed?
zavuch27 [327]
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8 0
4 years ago
What is the centripetal force that holds planets in orbit?
Alekssandra [29.7K]
<h2>Answer:</h2>

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5 0
4 years ago
An office worker has his lunch on the 53rd floor of an office building. In which case is the gravitational potential energy of t
Ann [662]

Options

a. The worker carried the lunch up to the 53rd floor in the elevator.

b. The worker got a ride in a helicopter to the top of the 68-floor building and then carried the lunch down in the elevator to the 53rd floor?

c. The Worker carried it up the stairs to the 53rd floor.

d. Gravitational potential energy does not depend on the path taken.

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The gravitational Energy would remain the same in all cases.

Explanation:

Gravitational Energy is a conservative energy and its potential energy comes from gravitational actions.

An instance is when someone lifts a weight from the floor to a certain height and then dropped the weight back to the floor; the work done by the field will not be altered at all; it'll be the same throughout.

If otherwise, it'll be against thermodynamics 2nd law of physics because the object would have remaining energy after returning to the starting point,

For this reason, the gravitational potential energy only depends from the height, and is independent from the path taken to reach there.

4 0
3 years ago
Baggage on the floor of the baggage car of a high-speed train is not prevented from moving other than by friction. The train is
stich3 [128]

Answer:

 μ = 0.36

Explanation:

This exercise must be solved in parts

Let's start by finding the acceleration of the train, using the kinematics relations

         v = v₀ - a t

         a = \frac{v - v_o}{t}

let's reduce the magnitudes to the SI system

         v = 66 mi / h (5280 ft / 1mile) (1h / 3600s) = 96.8 ft / s

         v₀ = 144 mi / h = 211.2 ft / s

let's calculate

          a = \frac{96.8 - 211.2}{12}

          a = - 9.53 ft / s²

Now we can use Newton's second law, for this let's set a reference system with the x axis parallel to the slope of the hill

let's break down the weight

            sin 5 = Wₓ / W

            cos 5 = W_y / W

            Wₓ = W sin 5

            W_y = W cos 5

Y axis

     N- W_y = 0

     N = W cos 5

   

X axis

      Wₓ -fr = m a

       mg sin 5 - fr = ma

the friction force has the expression

       fr = μ N

       fr = μ W cos 5

we substitute

        mg sin 5 - μ mg cos 5 = ma

        g sin 5 - μ g cos 5 = a

        μ = \frac{g \ sin 5 -a }{g \ cos 5}

        μ =  tan 5 - \frac{a}{ g \ cos 5}

let's calculate

       μ = tan 5 - (-9.53) / 32 cos 5

       μ = 0.08749 + 0.2733

       μ = 0.36

8 0
3 years ago
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