Answer:
4.635 *10^12 Neutrinos
Explanation:
Here in this question, we are to determine the number of neutrinos in billions produced, given the power generated by the proton-proton cycle.
We proceed as follows;
In proton-proton cycle generates 26.7 MeV of energy and in this cycle two neutrinos are produced.
From the question, we are given that
Power P = 9.9 watts = 9.9 J/s
Watts is same as J/s
The number of proton-proton cycles required to generate E energy is N = E / E '
Where E ' = Energy generated in proton-proton cycle which is given as 26.7 Mev in the question
Converting Mev to J, we have
= 26.7 x1.6 x10 -13 J
To get the number N which is the number of proton-proton cycle required, we have;
N = 9.9 /(26.7 x1.6 x10^-13) = 2.32 * 10^12
Since we have two proton cycles( proton-proton), it automatically means 2 neutrinos will be produced.
Therefore number of neutrions produced = 2 x Number of proton-proton cycles = 2 * 2.32 * 10^12 = 4.635 * 10^12 neutrinos
Answer:
Final Temperature is 310K
Explanation:
Given that:
Mass of O₂ gas = 2 kg
Pressure (P₁) = 100 kpa
Temperature (T₁) = 310K
We also have, ΔQ = ΔU + ΔW where ΔQ is the heat transferred into/out of the system, ΔW is the work done and ΔU is the change in internal energy of the system.
As soon as the wall is removed, the process called expansion process allows the evacuated chamber to be filled. Work done ΔW = PdV = 0, this is because P the external pressure against which the gas is expanding is zero, therefore the work done is zero.
ΔU which is highly dependent on the temperature is zero since there is no heat transferred in or out of the container due to it being insulated. This therefore means that the initial temperature is the same as the final temperature when the container if filled completely.
T₁ = Final temperature = 310 K
The final Temperature is therefore 310K
Here volume of gas is not given so question is solved assuming volume as 1 L.
The number of moles of 1 L gas present in the sealed container at a
pressure of 125 kPa at 25 degrees Celsius is 0.0067 moles.
The ideal gas law equation can be written as
PV = nR T
Here
P is the pressure of the gas in atm
V is the volume it occupies in L
n is the number of moles of gas present in the sample
R is the universal gas constant, equal to 0.0821 atm L/ mol K
T is the absolute temperature of the gas in Kelvin
Now, it's important to realize that the units you have for the volume, pressure, and temperature of the gas must match the unit used in the expression of the universal gas constant.
So
P = 125 kPa
1 atm = 760 kPa
P = 125/760 = 0.1644 atm
T = 25 degree celsius = 25 +273 = 298 K
Taking V = 1 L
So
n = PV/RT
n = 0.1644 x 1 / 0.0821 x 298
n = 0.0067 moles
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Answer:
b) 6
Explanation:
Given
v(t)=3t²+6t
X(0) = 2
X(1) = ?
Knowing that
v(t)=3t²+6t = dX/dt
⇒ ∫dX = ∫(3t²+6t)dt
⇒ X - X₀ = t³ + 3t²
⇒ X(t) = X₀ + t³ + 3t²
If X(0) = 2
⇒ X(0) = X₀ + (0)³ + 3(0)² = 2
⇒ X₀ = 2
then we have
X(t) = t³ + 3t² + 2
when
t = 1
X(1) = (1)³ + 3(1)² + 2
X(1) = 6