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2 years ago

The mass of Venus is

2 answers:

7 0

Mass Jupiter / mass of venus = 1898 * 10^24 / 4.87 * 10^24 = 1898 / 4.87 = 390 times heavier. I hope that comma is correct.

NeX [460]2 years ago

4 0

Answer:

The mass of Jupiter is about 389.7331 times the mass of Venus.

Step-by-step explanation:

The question is asking for how much the two masses vary from one another. Since the mass of Jupiter is greater than that of Venus, what value is to be multiplied by the mass of Venus that would give the mass of Jupiter?

Thus, to determine this, we divide the mass of Jupiter by the mass of Venus;

= $\frac{1898*10^{24} }{4.87*10^{24} }$

= $\frac{1898}{4.87}$

= 389.7331

Therefore, the mass of Jupiter is about 389.7331 times the mass of Venus.

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Sara plotted the locations of the trees in a park on a coordinate grid. She plotted an oak tree which was in the middle of the p

padilas [110]

Answer: $10.2\ yards$

Step-by-step explanation:

<h3> "Sara plotted the locations of the trees in a park on a coordinate grid. She plotted an oak tree, which was in the middle of the park, at the origin. She plotted a maple tree, which was 10 yards away from the oak tree, at the point (10,0) . Then she plotted a pine tree at the point (-2.4, 5) and an apple tree at the point (7.8, 5) What is the distance, in yards, between the pine tree and the apple tree in the</h3><h3>park?"</h3>

For this exercise you need to use the following formula, which can be used for calculate the distance between two points:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

In this case, you need to find distance, in yards, between the pine tree and the apple tree in the park.

You know that pine tree is located at the point (-2.4, 5) and the apple tree is located at the point (7.8, 5).

So, you can say that:

$x_2=-2.4\\x_1=7.8\\\\y_2=5\\y_1=5$

Knowing these values, you can substitute them into the formula and then evaluate, in order to find the distance, in yards, between the pine tree and the apple tree in the park.

This is:

$d=\sqrt{(-2.4-7.8)^2+(5-5)^2}=10.2\ yards$

8 0

2 years ago

A regular fish tank is 18 in wide 12 in deep and 24 in tall what is the volume of that fish tank

Lady bird [3.3K]

Answer:

(4,5 feet)³=4,5³ cubic feet

Step-by-step explanation:

6 0

2 years ago

Paco bought 3 CDs that cost d dollars each and a pack of gum for C cents. Write an expression for the total cost of his purchase

cupoosta [38]

Answer:

The correct option is A) $3d+C$ .

Step-by-step explanation:

Consider the provided information.

Paco bought 3 CDs that cost d dollars each.

Let d is the cost of each CDs.

The cost of 3 CDs will be 3 times of d.

This can be written as:

$3d$

He bought a pack of gum for C cent. Thus, we can say that the cost of pack of gum is C.

Now add the cost of gum in above expression.

$3d+C$

Hence, the required expression is $3d+C$ .

Thus, the correct option is A) $3d+C$ .

3 0

3 years ago

At Gloria’s Restaurant, the average diner tips the waiter 20% of their total bill (cost of meal). Jacob's bill was $66 How much

-Dominant- [34]

Answer:

Jacob should pay $13.20 for the tip.

Step-by-step explanation:

The equation is: (66)(0.2) = 13.20

6 0

2 years ago

Read 2 more answers

P and Q are two points on the line x - y + 1 = 0 and are at distance 5 from the origin. Find the area of the triangle OPQ.

Alecsey [184]

Answer:

P and Q are two points on the line x-y+1=0 and are at a distant of 5 units from the origin. Find the area of triangle POQ.

Step-by-step explanation:

P and Q are the intersection points of

x-y+1 = 0 and the circle x^2 + y^2 = 25

sub y = x+1 into the circle

x^2 + (x+1)^2 = 25

x^2 + x^2 + 2x + 1 - 25 = 0

x^2 + x - 12 = 0

(x+4)(x-3) = 0

x = 3 or x = -4

y = 4 or y = -3

so P(3,4) and Q(-4,3) are our two points

Height of triangle.

h = |0 - 0 + 1|/√2 = 1/√2

PQ = √( (-7)^2 + 1^2) = √50 = 5√2

area POQ = (1/2)(1/√2)(5√2) = 5/2 square units

hope this helped

7 0

1 year ago