Answer:

Step-by-step explanation:
Total number of toll-free area codes = 6
A complete number will be of the form:
800-abc-defg
Where abcdefg can be any 7 numbers from 0 to 9. This holds true for all the 6 area codes.
Finding the possible toll free numbers for one area code and multiplying that by 6 will give use the total number of toll free numbers for all 6 area codes.
Considering: 800-abc-defg
The first number "a" can take any digit from 0 to 9. So there are 10 possibilities for this place. Similarly, the second number can take any digit from 0 to 9, so there are 10 possibilities for this place as well and same goes for all the 7 numbers.
Since, there are 10 possibilities for each of the 7 places, according to the fundamental principle of counting, the total possible toll free numbers for one area code would be:
Possible toll free numbers for 1 area code = 10 x 10 x 10 x 10 x 10 x 10 x 10 = 
Since, there are 6 toll-free are codes in total, the total number of toll-free numbers for all 6 area codes = 
<em><u>Hi there! :)</u></em>
<em><u>Answer:</u></em>
<em><u>x>24</u></em>
<em><u>*The answer must have a positive sign and greater than symbol sign.*</u></em>
<em><u>Step-by-step explanation:</u></em>
First, you switch sides.

Then, you subtract by 18 from both sides of an equation.

Finally, you subtract by the numbers from left to right.

<u><em>Final answer is x>24</em></u>
I hope this helps you!
Have a nice day! :)
-Charlie
:D
Answer:
Domain: 0 minutes to time it takes to fill. Range: 0 to a 10,000 gallons
Step-by-step explanation:
Answer:
A.
Step-by-step explanation:
Factoring is the process of taking common terms out of an expression such that one can represent the expression as the result of smaller values. When given the following expression:

First, represent the linear term as the sum of two terms such that each term shares a common factor with the other terms in the expression.

Now take out the common factors,

Thus, the correct option is choice (A).
Answer:
3(x-2)+x=4x+6
Step-by-step explanation:
case 1) we have
3(x-2)+x=4x-6
Solve for x
3x-6+x=4x-6
4x-6=4x-6
0=0 ----> is true for any value of x
therefore
The equation has infinite solutions
case 2) we have
3(x-2)+x=2x-6
3x-6+x=2x-6
4x-2x=-6+6
2x=0
x=0
case 3) we have
3(x-2)+x=3x-3
3x-6+x=3x-3
4x-3x=-3+6
x=3
case 4) we have
3(x-2)+x=4x+6
3x-6+x=4x+6
4x-4x=6+6
0=12 ------> is not true
therefore
The equation has no solution