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Nina [5.8K]
3 years ago
7

How can i take out a random (double) number in between 5.0 to 15.0 in c++?

Computers and Technology
1 answer:
ollegr [7]3 years ago
3 0

Answer:

#include <iostream>

using namespace std;

int main() {

   srand(time(0));

   for(int i=0;i<5;i++)

   {

      double f = (double)rand() / RAND_MAX;//generating random numbers.

       double a= 5.0 + f * (15.0 - 5.0);//random numbers in range provided.

       cout<<a<<" ";

   }

return 0;

}

Explanation:

The above program generate five random numbers in the range 5.0 to 15.0.The function rand() is used to generate random numbers.First we have to call srand(time(0)) otherwise the rand() function will generate same random numbers over and over every time.

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Answer:

Probability Distribution={(A, 4/7), (B, 2/7), (C, 1/7)}

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iii

If X={A,B,C}

and P(Xi)={4/7,2/7,1/7}

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Entropy, H(X)=-{P(A) Id P(A) +P(B) Id P(B) + P(C) Id P(C)}

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P(B)=1/3

P(A)=2/3

H(X|Y="not C")= -(1/3)Id(I/3) -(2/3)Id(2/3)

=0.54902 bits per symb

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