I need help, It is a written problem
1 answer:
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Answer:
C. 6
Step-by-step explanation:
Recall that inverse variation is given by:
Where <em>k</em> is the constant of variation.
We know that <em>y</em> = 48 when <em>x</em> = 3. Substitute:
Solve for <em>k: </em>
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Hence, our equation is:
We want to find <em>x</em> when <em>y</em> = 24. Substitute:
Cross-multiply:
Divide both sides by 24. Hence:
Our answer is C.
Answer:
x = 0 , -2 , 1 +i√3 ; 1 - i√3
Step-by-step explanation:
2x⁴ + 16x = 0
2x(x³ + 8) = 0
2x(x³ + 2³) = 0
2x (x + 2)(x² -2x + 2²) = 0 {a³ + b³ = (a + b)*(a² -ab +b²}
2x = 0
x = 0
x + 2 = 0
x = -2
x² - 2x + 4 = 0
a = 1 ; b = -2 and c = 4
D = b² - 4ac = (-2)² - 4*1*4= 4 - 16 = -12
root = (-b ± √D)/2a
= (-(-2) ± 2i√3)/2*1
= (2 ± 2i√2)/2