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Semmy [17]
2 years ago
6

In a certain lottery, 5 numbers between 1 and 13 inclusive are drawn. These are the winning numbers. How many different sections

are possible? Assume that the order in which the numbers are drawn is not important.
a.1287
b.154,440
c.371,293
d.120
Mathematics
2 answers:
Molodets [167]2 years ago
8 0
13 choose 5=13x12x11x10x9x8!/5x4x3x2x8!=1287
☺☺☺☺
Alex_Xolod [135]2 years ago
7 0

Answer: 1287

Step-by-step explanation:

When order of selecting things does not matter, then the combination od n things taking r at a time is given by :-

^nC_r=\dfrac{n!}{r!(n-r)!}

Given : The total numbers in lottery = 13

The total numbers to choose to win the lottery =- 5

Then , the combination of 13 numbers taken 5 at a time is given by :-

^{13}C_r=\dfrac{13!}{5!(13-5)!}=1287

Hence, the number of different selections = 1287

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I really need help and this answered ASAP. thank you and sorry.
Semenov [28]

9514 1404 393

Answer:

  $2.50

Step-by-step explanation:

The question asks for the total cost of a notebook and pen together. We don't need to find their individual costs in order to answer the question.

Sometimes we get bored solving systems of equations in the usual ways. For this question, let's try this.

The first equation has one more notebook than pens. The second equation has 4 more notebooks than pens. If we subtract 4 times the first equation from the second, we should have equal numbers of notebooks and pens.

  (8n +4p) -4(3n +2p) = (16.00) -4(6.50)

  -4n -4p = -10.00 . . . . . . . . . . . simplify

  n + p = -10.00/-4 = 2.50 . . . . divide by the coefficient of (n+p)

The total cost for one notebook and one pen is $2.50.

__

<em>Additional comment</em>

The first equation has 1 more notebook than 2 (n+p) combinations, telling us that a notebook costs $6.50 -2(2.50) = $1.50. Then the pen is $2.50 -1.50 = $1.00.

One could solve for the costs of a notebook (n) and a pen (p) individually, then add them together to answer the question. We judge that to be more work.

4 0
3 years ago
Read 2 more answers
What is the value of x
borishaifa [10]
x^2=4^2+4^2\\&#10;x^2=2\cdot16\\&#10;x^2=32\\&#10;x=\sqrt{32}=4\sqrt2
5 0
3 years ago
Solve the following quadratic equation by the square root method. (Y-9)^2=64
enot [183]

Hello!

To solve this, first perform the opposite operation for the last operation (on the left side) on both sides. The last operation of the left side is squaring. Therefore, square root both sides.

(y - 9)^{2}  = 64

y - 9 = ±\sqrt{64}

y - 9 = ±8

Please note that you must include ±. This is because the square root of 64 can be either positive or negative, as a square of either a positive or negative number is positive.

Now, add 9 to both sides.

y  = 9±8

There are 2 solutions from here. One comes from adding 8, and the other subtracting 8. Therefore, the two solutions are:

y = 9 + 8 = 17

y = 9 - 8 = 1

Therefore, your two solutions are 17 and 1.

Hope this helps!

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Alexeev081 [22]
Download got it and see if it answer faster !
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