Question

Find the coordinates of the intersection of the medians of △ ????BC given ????(2, 4), ????(−4, 0), and ????(3, −1).

Answer 1

Answer:

The coordinates of the intersection of the medians of △ABC is (1/3, 1).

Step-by-step explanation:

Consider the vertices of △ABC are A(2, 4), B(−4, 0), and C(3, −1).

Intersection of the medians of a triangle is known as centroid.

Formula for centroid of a triangle is

$Centroid=(\dfrac{x_1+x_2+x_3}{3},\dfrac{y_1+y_2+y_3}{3})$

Using the above formula the centroid of △ABC is

$Centroid=(\dfrac{2-4+3}{3},\dfrac{4+0-1}{3})$

$Centroid=(\dfrac{1}{3},\dfrac{3}{3})$

$Centroid=(\dfrac{1}{3},1)$

Therefore the coordinates of the intersection of the medians of △ABC is (1/3, 1).