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3 years ago

Can you help me please somebody

Mathematics

1 answer:

PtichkaEL [24]3 years ago

6 0

What do you need to help?

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Solve <br> 3c-5=2c+5<br> please naswer fast and I will give you 5 stars

Masja [62]

Answer:

Step-by-step explanation:

3c - 5 =2c +5

3c - 2c =5 +5

c=10

4 0

4 years ago

Westley and Buttercup are each saving money. Westley starts with $85 in in his savings and add $5 per week (y=85+5x)

love history [14]

Answer:

After 5 weeks.

Step-by-step explanation:

Westley starts with $85 and saves $5 per week. So:

$y=85+5x$

Buttercup starts with $10 and saves $20 per week. So:

$y=10+20x$

When they have the same amount of money, the two equations will be equal to each other. Therefore:

$85+5x=10+20x$

Solve for x. Subtract 10 from both sides:

$75+5x=20x$

Subtract 5x from both sides:

$75=15x$

Divide both sides by 15:

$x=5$

Westley and Buttercup will have the same amount of money after 5 weeks.

5 0

3 years ago

Factor x^2+ 5x + 6<br> pleaseee

alekssr [168]

Answer:

( x + 2 ) ( x +3 )

6 0

3 years ago

Read 2 more answers

Write the standard form of the equation of the line described.

Vitek1552 [10]

The first line equation: y = -2/7x - 5; m1 = -7/2
The second line passes through (2,4) and is perpendicular to the first line.

Therefore,
The gradient of first line = -1/m1 = -1/(-2/7) = 7/2

Then, the equation of the second line is;
y = 7/2x+b

Substituting for the coordinates given;
4 = 7/2(2)+b
4 = 7+b
b = 4-7 = -3

Therefore, the equation of the second line is;
y = 7/2x - 3

In standard form, the equation this equation can be written as:
y(2) = 7x - 3(2)
2y = 7x - 6
7x -2y - 6 = 0 -----> standard form.

8 0

4 years ago

6. (x + 2)(3x - 1) - (x + 4)(x - 7)<br> i’m confused

Lera25 [3.4K]

Answer:

$\large\boxed{(x+2)(3x-1)-(x+4)(x-7)=2x^2+8x+26}$

Step-by-step explanation:

$(x+2)(3x-1)-(x+4)(x-7)\\\\\text{Use FOIL:}\ (a+b)(c+d)=ac+ad+bc+bd\\\\(x+2)(3x-1)=(x)(3x)+(x)(-1)+(2)(3x)+(2)(-1)\\\\=3x^2-x+6x-2=3x^2+(-x+6x)-2=3x^2+5x-2\\\\(x+4)(x-7)=(x)(x)+(x)(-7)+(4)(x)+(4)(-7)\\\\=x^2-7x+4x-28=x^2+(-7x+4x)-28=x^2-3x-28\\\\(x+2)(3x-1)-(x+4)(x-7)=(3x^2+5x-2)-(x^2-3x-28)\\\\=3x^2+5x-2-x^2-(-3x)-(-28)=3x^2+5x-2-x^2+3x+28\\\\=(3x^2-x^2)+(5x+3x)+(-2+28)\\\\=2x^2+8x+26$

7 0

4 years ago

Read 2 more answers