Answer:
Matrix multiplication is not conmutative
Step-by-step explanation:
The matrix multiplication can be performed if the number of columns of the first matrix is equal to the number of rows of the second matrix
Let A with dimension mxn and B with dimension nxp represent two matrix
The multiplication of A by B is a matrix C with dimension mxp, but the multiplication of B by A is can't be calculated because the number of columns of B is not the number of rows of A. Therefore, you can notice that is not conmutative in general.
But even if the multiplication of AB and BA is defined (For example if A and B are squared matrix of 2x2) the multiplication is not necessary conmutative.
The matrix multiplication result is a matrix which entries are given by dot product of the corresponding row of the first matrix and the corresponding column of the second matrix:
![A=\left[\begin{array}{ccc}a11&a12\\a21&a22\end{array}\right]\\B= \left[\begin{array}{ccc}b11&b12\\b21&b22\end{array}\right]\\AB = \left[\begin{array}{ccc}a11b11+a12b21&a11b12+a12b22\\a21b11+a22b21&a21b12+a22b22\end{array}\right]\\\\BA=\left[\begin{array}{ccc}b11a11+b12a21&b11a12+b12a22\\b21a11+b22ba21&b21a12+b22a22\end{array}\right]](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Da11%26a12%5C%5Ca21%26a22%5Cend%7Barray%7D%5Cright%5D%5C%5CB%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Db11%26b12%5C%5Cb21%26b22%5Cend%7Barray%7D%5Cright%5D%5C%5CAB%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Da11b11%2Ba12b21%26a11b12%2Ba12b22%5C%5Ca21b11%2Ba22b21%26a21b12%2Ba22b22%5Cend%7Barray%7D%5Cright%5D%5C%5C%5C%5CBA%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Db11a11%2Bb12a21%26b11a12%2Bb12a22%5C%5Cb21a11%2Bb22ba21%26b21a12%2Bb22a22%5Cend%7Barray%7D%5Cright%5D)
Notice that in general, the result is not the same. It could be the same for very specific values of the elements of each matrix.
A rhombus<span> has </span>rotational symmetry<span>. It is a </span>symmetric<span> shape that can be rotated and still appear the same. A </span>rhombus<span> has two-fold </span>symmetry<span>, meaning that is can be rotated 180 degrees and appear the same.</span>
Answer:
Presumably you're solving for x here? Without further information we'll assume that.
With that in mind, x is approximately equal to 0.86 and -0.46
Step-by-step explanation:
Let's start by putting it in the usual ax² + bx + c format.
let's solve it. First we'll multiply both sides by five, making the first term a perfect square:
Now we'll add 11 to both sides:
Which makes the left side a perfect square:
And now we can solve for x:
Note that there's no apparent way of drawing the ± symbol when editing equations, so take that + sign as actually being ±.
That gives us two answers:
Answer:
X : ___ 0 ____ 1 _____ 2 ______ 3
P(X) : _ 6/15 __ 5/15__ 3/15 ____ 1/15
Step-by-step explanation:
From the data, to produce a probability distribution for the data :
X : number of times blood is drawn ;
P(x) : probability that blood is drawn at X times
Hence, the probability distribution table for the data Given goes thus :
X : ___ 0 ____ 1 _____ 2 ______ 3
P(X) : _ 6/15 __ 5/15__ 3/15 ____ 1/15
Probability that blood is drawn 0 times = 6/15
Probability that blood is drawn 1 time = 5/15
Probability that blood is drawn 2 times = 3/15
Probability that blood is drawn 3 times = 1/15
(6/15 + 5/15 + 3/15 + 1/15) = 1
Answer:
C
Step-by-step explanation:
The strip patterns new image and pre image orientation are vertical so anything that has horizontal translation in it is wrong
- C is right becuase we can reflect the b across a vertical line to get to P
