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Delvig [45]
3 years ago
5

How do I graph this? In picture below please include the graph

Mathematics
1 answer:
Savatey [412]3 years ago
3 0

Answer:

See the attached figure.

Step-by-step explanation:

The given function is called piecewise function which is the function that can be in pieces, i.e: defined by multiple sub-functions.

f(x)=\left \{ {{2x} \ , \ x\geq3  \atop {-\frac{1}{3}x+7 \ , \ x\leq 3 }} \right.

So, need to graph 2x in the interval [3,∞)

And graph -(1/3) x + 7  in the interval (-∞,3]

We will find that f(3) at the function 2x will be equal f(3) at the function -(1/3) x + 7

Which mean the function is continuous.

The attached figure represents the graph of function, it was graphed using the tables on the graph.

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Factor out the GCF from the terms of the polynomial −2x5 − 6x3 − 16x2.
Ahat [919]

Answer:

2x^2(x^3+3x+8)

Step-by-step explanation:

Factor out the gcf which in this case is -2x^2 because that's the greatest factor all of the terms have in common this results in -2x^2(x^3+3x+8)

Btw the ^ represents the exponent

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3 years ago
Which quadrilateral does NOT have two pairs of parallel sides?
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It a................
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As the age of the car increases, its value decreases. Which
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The answer is A.......
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Full steps and all reasons, thanks!​
Nataly_w [17]

You can focus on the two sub-triangles ABC and ACD

We know that they are both right triangles, because we're given that AC and BD are perpendicular.

The sides AB and AD are the hypothenuses of these triangles, so we know their length through the pythagorean theorem:

AD^2 = AC^2+CD^2

AB^2 = AC^2+BC^2

But since we're given BC=CD, the expressions for AD and AB are actually the same expression. This proves that AD=AB, and thus that the triangle is isosceles.

8 0
3 years ago
5. Solve the equation z^2 + 4z - 9 = 0 by completing the square.
Luba_88 [7]

Answer:

A. Z = 2 + N13

Step-by-step explanation:

Let's solve your equation step-by-step.

0=z2+4z−9

Step 1: Subtract z^2+4z-9 from both sides.

0−(z2+4z−9)=z2+4z−9−(z2+4z−9)

−z2−4z+9=0

For this equation: a=-1, b=-4, c=9

−1z2+−4z+9=0

Step 2: Use quadratic formula with a=-1, b=-4, c=9.

z=

−b±√b2−4ac

2a

z=

−(−4)±√(−4)2−4(−1)(9)

2(−1)

z=

4±√52

−2

z=−2−√13 or z=−2+√13

8 0
3 years ago
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