X + k y = 1
k x + y = 1 / * ( - k )
----------------
x + k y = 1
- k² x - k y = - k
--------------------
x - k² x = 1 - k
x ( 1 - k² ) = 1 - k
x = ( 1 - k ) / ( 1 - k² ) = ( 1 - k ) / ( 1 - k ) ( 1 + k )
y = 1 - k( 1 - k )/( 1 - k² )
y = ( 1 - k ) / ( 1 - k² ) = ( 1 - k ) / ( 1 - k ) ( 1 + k )
a ) For k = - 1 this system has no solution.
b ) For k ≠ - 1 and k ≠ 1, the system has unique solution:
( x , y ) = ( 1/ (1 + k) , 1/( 1 + k ) ).
c ) For k = 1, there are infinitely many solutions.
the domain: no real numbers so its negative infinity, positive infinity
For this case we have the following equation:
y = x2-4x + 3
Deriving we have the following equation:
y '= 2x-4
We equal zero and clear x:
2x-4 = 0
x = 4/2
x = 2
Substituting in the given equation we have:
y = (2) ^ 2-4 (2) +3
y = 4-8 + 3
y = -1
The vertex will be the ordered pair:
(x, y) = (2, -1)
Answer:
(x, y) = (2, -1)
option B
Answer:
1. Locate the y-intercept on the graph and plot the point.
2. From this point, use the slope to find a second point and plot it.
3. Draw the line that connects the two points.