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3 years ago

Can someone tell me the answers

Mathematics

1 answer:

LiRa [457]3 years ago

4 0

Question 4- is 32.25
question 5- is 12.4
question 6 -is 14/17
question 7 - is 10.7

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Select all equations that have graphs with the same y-intercept.

vlada-n [284]

Answer:

y = 3x - 8

y = (1/3)x - 8

y= 5x - 8

y= 2x - 8

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3 years ago

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The CONIC SECTIONS get this name from the fact that they are formed by the intersection of a cone and a A) plane. B) sphere. C)

Tema [17]

It is a cylinder.........

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3 years ago

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Y=3x-5 y=6x-8 show all steps and write the solution

m_a_m_a [10]

Step 1: Set the two equations equal to each other and solve for x.

3x -5 = 6x - 8

3x + (-5+5) = 6x -8 + 5

(3x - 6x) = (6x - 6x) - 3

-3x/-3 = -3/-3

x = 1

Step 2: To solve for y take one of the given equation of your choice (for the purpose of this explanation I will only do y = 3x - 5) and replace x with 1, then solve for y

y = 3(1) - 5

y = 3 - 5

y = -2

(1,-2)

Check:

-2 = 3(1) - 5 ---> - 2 = -2

-2 = 6(1) - 8 ---> -2 = -2

Hope this helped!

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2 years ago

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A group of three undergraduate and five graduate students are available to fill certain student government posts. If four studen

creativ13 [48]

Answer:

$Pr = 0.4286$

Step-by-step explanation:

Given

Let

$U \to\\$ Undergraduates

$G \to$ Graduates

So, we have:

$U = 3; G =5$ -- Total students

$r = 4$ --- students to select

Required

$P(U =2)$

From the question, we understand that 2 undergraduates are to be selected; This means that 2 graduates are to be selected.

First, we calculate the total possible selection (using combination)

$^nC_r = \frac{n!}{(n-r)!r!}$

So, we have:

$Total = ^{U + G}C_r$

$Total = ^{3 + 5}C_4$

$Total = ^8C_4$

$Total = \frac{8!}{(8-4)!4!}$

$Total = \frac{8!}{4!4!}$

Using a calculator, we have:

$Total = 70$

The number of ways of selecting 2 from 3 undergraduates is:

$U = ^3C_2$

$U = \frac{3!}{(3-2)!2!}$

$U = \frac{3!}{1!2!}$

$U = 3$

The number of ways of selecting 2 from 5 graduates is:

$G = ^5C_2$

$G = \frac{5!}{(5-2)!2!}$

$G = \frac{5!}{3!2!}$

$G =10$

So, the probability is:

$Pr = \frac{G * U}{Total}$

$Pr = \frac{10*3}{70}$

$Pr = \frac{30}{70}$

$Pr = 0.4286$

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2 years ago

What is the value of fraction 1 over 2x3 + 5.2y when x = 2 and y = 3?

Leokris [45]

The answer should be 18.6, just substitute x for 2 and y for 3 and solve using PEMDAS :)

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3 years ago