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ahrayia [7]
3 years ago
9

A parallelogram with sides of 6 and 10 has an area of 30. Find the measure of the small angle of the parallelogram.

Mathematics
2 answers:
Elina [12.6K]3 years ago
7 0

Answer:

45

Step-by-step explanation:


sergeinik [125]3 years ago
4 0
Parallelogram area = base * height
30 = 10 * height
height = 3
Sine Parallelogram Angle = height / side
Sine (Angle) = 3 / 6
Sine Angle = .5
Angle = 30 degrees


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The average value of a function f over the interval [−2,3] is −6 , and the average value of f over the interval [3,5] is 20. Wha
Xelga [282]

Answer:

The average value of f over the interval [-2,5] is \frac{10}{7}.

Step-by-step explanation:

Let suppose that function f is continuous and integrable in the given intervals, by integral definition of average we have that:

\frac{1}{3-(-2)} \int\limits^{3}_{-2} {f(x)} \, dx = -6 (1)

\frac{1}{5-3} \int\limits^{5}_{3} {f(x)} \, dx = 20 (2)

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\frac{F(3)-F(-2)}{3-(-2)} = -6

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We obtain the average value of f over the interval [-2, 5] by algebraic handling:

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