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Maurinko [17]
3 years ago
11

A better alternative to direct observation to collect data is through_____, which are often/are more costly.

Mathematics
1 answer:
shtirl [24]3 years ago
6 0
A. Experimentation -
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Please help. I got an answer but I do not think it is correct.
AVprozaik [17]

Answer: 81


Step-by-step explanation:

(3^2)^2=81

Hope that helped

8 0
3 years ago
(Find the HCF of):<br>p^2+4pq+4q^2, p^4 + 8pq^3 and 3p^4 - 10p^2q^2+ p^3q​
kow [346]

Answer:

12pq

Step-by-step explanation:

i dont know tbh but i try my best to help out now anyways

5 0
3 years ago
Which of the following equations represents a line parallel to the line given by y=5x +9?
erma4kov [3.2K]

Answer:

y = 5x + 1

Step-by-step explanation:

Lines that are parallel to each other on a graph would have the same slope but different y-intercepts. When option A's equation is graphed along with the line given in the question, the lines appear to be parallel.  

Option A should be the correct answer.

7 0
3 years ago
Factor 16x+40y I don't know how to do this
Marizza181 [45]

Answer:

8(2x + 5y)

Step-by-step explanation:

You cant fact (take out) 8 from both 16 and 40 since 8 is a factor for both.

4 0
3 years ago
Read 2 more answers
I need help! Will mark Brainliest for full answer!!!
Softa [21]

<u><em>Answer:</em></u>

Part a .............> x = 11

Part b .............> k = 57.2

Part c .............> y = 9.2

<u><em>Explanation:</em></u>

The three problems deal with inverse variation between two variables

An inverse variation relation between two variables means that when one of the variables increases, the other will decrease (and vice versa)

<u>Mathematically, an inverse variation relation is represented as follows:</u>

y = \frac{k}{x}

where x and y are the two variables and k is the constant of variation

<u><em>Now, let's check the givens:</em></u>

<u>Part a:</u>

We are given that y = 3 and k = 33

<u>Substitute in the original relation and solve for x as follows:</u>

y = \frac{k}{x}\\ \\3 = \frac{33}{x}\\ \\x=\frac{33}{3}=11

<u>Part b:</u>

We are given that y = 11 and x = 5.2

<u>Substitute in the original relation and solve for k as follows:</u>

y=\frac{k}{x}\\ \\11=\frac{k}{5.2}\\ \\k=11*5.2=57.2

<u>Part c:</u>

We are given that x=7.8 and k=72

<u>Substitute in the original relation and solve for y as follows:</u>

y=\frac{k}{x}=\frac{72}{7.8}=9.2 to the nearest tenth

Hope this helps :)

6 0
3 years ago
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