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Nata [24]
3 years ago
9

Evaluate (4.0x10^5)(7.0x10^7)

Mathematics
1 answer:
nikdorinn [45]3 years ago
5 0

Answer:

2.8(10^13)

Step-by-step explanation:

4.0 times 7.0 equals 28.0.

(10^5) TIMES (10^7) equals 10^12 (add the exponents 5 and 7 together)

Final answer:  28.0(10^12), or, better yet, 2.8(10^13)

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2 years ago
Express 9x3 + 6x2 – 3x in factored form. 3x(x – 1)(3x – 1) 3x(x – 1)(3x + 1) 3x(x + 1)(3x + 1) 3x(x + 1)(3x – 1)
swat32
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3 years ago
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3 years ago
Data were collected on the amount spent by 64 customers for lunch at a major Houston restaurant. These data are contained in the
galina1969 [7]

Answer:

a. The margin of error is 2.29.

b. 19.23 to 23.81

Step-by-step explanation:

The sample size is n=64.

We start by calculating the sample mean and standard deviation with the following formulas:

M=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\s=\sqrt{\dfrac{1}{n-1}\sum_{i=1}^n\,(x_i-M)^2}

The sample mean is M=21.52.

The sample standard deviation is s=6.89.

We have to calculate a 99% confidence interval for the mean.

The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.

When σ is not known, s divided by the square root of N is used as an estimate of σM:

s_M=\dfrac{s}{\sqrt{N}}=\dfrac{6.89}{\sqrt{64}}=\dfrac{6.89}{8}=0.861

The degrees of freedom for this sample size are:

df=n-1=64-1=63

The t-value for a 99% confidence interval and 63 degrees of freedom is t=2.656.

The margin of error (MOE) can be calculated as:

MOE=t\cdot s_M=2.656 \cdot 0.861=2.29

Then, the lower and upper bounds of the confidence interval are:

LL=M-t \cdot s_M = 21.52-2.29=19.23\\\\UL=M+t \cdot s_M = 21.52+2.29=23.81

The 99% confidence interval for the mean is (19.23, 23.81).

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3 years ago
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Anit [1.1K]

Answer:

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Step-by-step explanation:

In this question, we can use the pythagoras theorem to solve it.

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