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earnstyle [38]
3 years ago
10

Find the slope of the line on the graph. Write your answer as a fraction or a whole number, not a mixed number or decimal.

Mathematics
1 answer:
Andreyy893 years ago
7 0

Answer:

1

Step-by-step explanation:

Slope (m) of the line can be derived using the following formula below:

m = \frac{y2 - y1}{x2 - x1}

To solve this, we can pick any two points on the line, and use the coordinates of the points to solve for the slope (m) of the line.

To find the slope (m) of the line given, let's use the coordinates of the points where the line intercepts the y-axis and the x-axis.

Thus, when x = 0, y = 3. Let's make this the first pair of coordinates at the point where the line intercepts the y-axis.

At the point where the line intercepts the x-axis, when x = -3, y = 0.

We now have the following points => in the following format (x, y) as:

Point 1 => (0, 3). Let this be (x1, y1)

Point 2 => (-3, 0). Let this be (x2, y2)

==>Let's find slope (m):

m = \frac{y2 - y1}{x2 - x1}

m = \frac{0 - 3}{-3 - 0}

m = \frac{-3}{-3}

m = 1

Slope (m) = 1

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Elanso [62]
The answer is 14.5 because :

2 times 2?5 = 5 so the denominator must have the same done, so 7.5 x 2.5 is 17.5. Subtract 3 from 7.5 and you get 14 .5 . So, m+ 14.5
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What is the best answer to this question, y=3×+6?<br> What's the y intercept?
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3 years ago
You roll a pair of honest dice. If you roll a total of 7, you win $18; if you roll a total of 11, you win $54; if you roll any o
amm1812
Answer: -1
The negative value indicates a loss

============================================================

Explanation:

Define the three events
A = rolling a 7
B = rolling an 11
C = roll any other total (don't roll 7, don't roll 11)

There are 6 ways to roll a 7. They are
1+6 = 7
2+5 = 7
3+4 = 7
4+3 = 7
5+2 = 7
6+1 = 7
Use this to compute the probability of rolling a 7
P(A) = (number of ways to roll 7)/(number total rolls) = 6/36 = 1/6
Note: the 36 comes from 6*6 = 36 since there are 6 sides per die

There are only 2 ways to roll an 11. Those 2 ways are:
5+6 = 11
6+5 = 11
The probability for event B is P(B) = 2/36 = 1/18

Since there are 6 ways to roll a "7" and 2 ways to roll "11", there are 6+2 = 8 ways to roll either event. 
This leaves 36-8 = 28 ways to roll anything else
P(C) = 28/36 = 7/9

-----------------------------

In summary so far,
P(A) = 1/6
P(B) = 1/18
P(C) = 7/9

The winnings for each event, let's call it W(X), represents the prize amounts.
Any losses are negative values
W(A) = amount of winnings if event A happens 
W(B) = amount of winnings if event B happens
W(C) = amount of winnings if event C happens
W(A) = 18
W(B) = 54
W(C) = -9

Multiply the probability P(X) values with the corresponding W(X) values
P(A)*W(A) = (1/6)*(18) = 3
P(B)*W(B) = (1/18)*(54) = 3
P(C)*W(C) = (7/9)*(-9) = -7

Add up those results
3+3+(-7) = -1

The expected value for this game is -1.
The player is expected to lose on average 1 dollar per game played.


Note: because the expected value is not 0, this is not a fair game.


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