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Rina8888 [55]
3 years ago
8

Can someone please help me with this..? (Will give brainlest)

Mathematics
2 answers:
Sindrei [870]3 years ago
6 0

Answer:

(80, 40)

Step-by-step explanation:

See attachment for locations

gayaneshka [121]3 years ago
5 0

Step-by-step explanation:

The first purple dot is (40,20)

The second purple dot is (20,50)

The third purple dot is (60,20)

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( \frac{r}{s} )(6)= \frac{r(6)}{s(6)}

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s(6)=2(6)+1=12+1=13
( \frac{r}{s} )(6)= \frac{r(6)}{s(6)}= \frac{17}{13}



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<img src="https://tex.z-dn.net/?f=%5Csqrt%7B6y%2B7%7D%3D5%2B%5Csqrt%7By-3%7D%20%5C%5CI%20get%20how%20to%20begin%20this%20but%20h
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Answer:

\sqrt{6y+7} -\sqrt{y-3} =5\\(\sqrt{6y+7} -\sqrt{y-3} )^2=5^2\\\sqrt{6y+7} ^2+\sqrt{y-3} ^2-2\sqrt{(6y+7)(y-3)} =25\\6y+7+y-3-25=2\sqrt{(6y+7)(y-3)} \\7y-21=2\sqrt{(6y+7)(y-3)} \\(7y-21)^2=(2\sqrt{6y^2-18y+7y-21} )^2\\49y^2+441-294y=4(6y^2-11y-21)\\49y^2+441-294y=24y^2-44y-84\\49y^2-24y^2+441+84-294y+44y=0\\25y^2-250y+525=0\\25(y^2-10y+21)=0\\y^2-10y+21=0\\y^2-7y-3y+21=0\\y(y-7)-3(y-7)=0\\(y-7)(y-3)=0\\y-7=0 or y-3=0\\y=7 ,y=3

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3 years ago
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