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In-s [12.5K]
3 years ago
14

What coefficients would balance equation: __MgS+__Na2O=_Na2S+__MgO

Chemistry
1 answer:
faust18 [17]3 years ago
6 0
Hey there !

<span>Balanced equation:

1 MgS +1 Na2O = 1 Na2S + 1 MgO
</span>
MgS = 1
Na2O = 1
Na2S = 1
MgO = 1

Answer D
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The answer is a compound machine!

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How does the energy of an electron close to the nucleus compare to the energy of electrons farther away from the nucleus?
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The electrons closer to the nucleus would have more energy than the electrons farther away from the nucleus.
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A gas cylinder is filled with argon at a pressure of 177 atm and 25°C. What is the gas pressure when the temperature of the cyli
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277.79 atm is the calculated gas pressure.

The ideal gas is a fictitious concept used to study how real gases behave by comparing them to their deviations. The pressure-temperature rules are followed by an ideal gas.

177 atm is the initial pressure. The starting temperature is 298 K (25 °C = 25 + 273 °C).

195°C = 195+273

= 468K is the final temperature.

The pressure temperature relation illustrated below can be used to get the final pressure.

P1/T1 = P2/T1

= P1T2/T1

= 177 atm 468 K /298 K

= 277.97 atm

The final pressure is therefore 277.97 atm.

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2 years ago
Which element is the first element in group 13 of the periodic table of elements?​
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a 5L container contains 3 moles of helium and 4 moles of hydrogen at a pressure of 9 atms maintaining a constant T and additiona
Stells [14]

Answer:

7.71 atm

Explanation:

Given the following data:

V = 5 L

n_{He} = 3 mol

n_{H_2} = 4 mol

p_1 = 9 atm

T = const

According to the ideal gas law, we know that the product between pressure and volume of a gas is equal to the product between moles, the ideal gas law constant and the absolute temperature:

pV = nRT

Since the temperature and the ideal gas constant are constants, as well as the fixed container volume of 5 L, we may rearrange the equation as:

\frac{p}{n}=\frac{RT}{V}=const

This means for two conditions, we'd obtain:

\frac{p_1}{n_1}=\frac{p_2}{n_2}

Given:

p_1 = 9 atm

n_1 = n_{initial total} = n_{He} + n_{H_2} = 3 mol + 4 mol = 7 mol

n_2 = n_{final total} = n_{He} + n_{H_2} = 3 mol + 4 mol + 2 mol = 9 mol

Solve for the final pressure:

p_2 = p_1\cdot \frac{n_2}{n_1}

Now, according to the Dalton's law of partial pressures, the partial pressure is equal to the total pressure multiplied by the mole fraction of a component:

p_{H_2}=\chi_{H_2}p_2

Knowing that:

p_2 = p_1\cdot \frac{n_2}{n_1}

And:

\chi_{H_2}=\frac{n_H_2}{n_2}

The equation becomes:

p_{H_2}=\chi_{H_2}p_2=p_1\cdot \frac{n_2}{n_1}\cdot \frac{n_H_2}{n_2}=p_1\cdot \frac{n_H_2}{n_1}

Substituting the variables:

p_{H_2}=9 atm\cdot \frac{4 mol + 2 mol}{7 mol}=7.71 atm

6 0
3 years ago
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