Answer:
Final pressure of the gas remaining in the first container is 3.5 atm
Explanation:
Since it is given that temperature is constant , we can apply -
PV=constant , where
P = Pressure of the gas
V = Volume of the container in which the gas is contained
Initially,
For container 1 -
= 4 atm
= 6 L
Finally,
For container 2 -
= 3 atm
= 1 L
For container 1 -
= ?
= 6 L
∴ 
= 
+ 

∴ 4×6 = (
×6) +(3×1)
∴
= 3.5 atm
I think it might be D or B
And my other two might be A or C
I believe it is decomposition, neutralization, combustion
Answer:
0.47dm³
Explanation
Given parameters :
Molarity of NaCl = 6.67M
Number of moles = 3.12mol
Volume of NaCl =?
Volume of NaCl = number of moles/Molarity
Volume of NaCl = 3.12mol/6.67M
Volume of NaCl = 0.47dm³