#1 is 6 
#2 During chemistry lab, Mrs. Black’s students placed an antacid tablet in a zip lock bag. They recorded the mass of the tablet in the bag. Then they carefully added 50 grams of water and quickly sealed the bag. The tablet began to fizz and soon disappeared. The bag was filled with gas and it felt cold to the touch.
 
        
             
        
        
        
<span>The type of bond that a
Phosphorous pentachloride have is an Ionic Bonding. It is a form of chemical
bond that encompasses the electrostatic attraction between oppositely charged
ions which serves as the primary interaction happening in ionic compound. Phosphorus
has 5 valence electrons and Chlorine has 7 valence electrons. Phosphorus contributes
1 electron to each chlorine and all the 6 achieve 8 electrons in the outer
shell thus creating an ionic bond.</span>
 
        
                    
             
        
        
        
The answer is 34.1 mL.
Solution:
Assuming ideal behavior of gases, we can use the universal gas law equation
     P1V1/T1 = P2V2/T2
The terms with subscripts of one represent the given initial values while for terms with subscripts of two represent the standard states which is the final condition. 
At STP, P2 is 760.0torr and T2 is 0°C or 273.15K. Substituting the values to the ideal gas expression, we can now calculate for the volume V2 of the gas at STP:
     (800.0torr * 34.2mL) / 288.15K = (760.0torr * V2) / 273.15K
     V2 = (800.0torr * 34.2mL * 273.15K) / (288.15K * 760.0torr)
     V2 = 34.1 mL
        
                    
             
        
        
        
Quantitative observations include numerical data. Ex: 32 degrees, 10 inches, etc.
 
        
                    
             
        
        
        
Answer:
The change in internal energy of the heater is 0 kJ
Explanation:
∆U = Q - W
Q is quantity of heat transferred = 1 kJ
W is work done on the heater = 1 kJ
Change in internal energy (∆U) = 1 - 1 = 0 kJ