Question

How many moles of hydrogen gas will be produced when 12 g of Mg will react completely with excess of an acid according to the following reaction? 2 Mg + 2 HCI — 2 MgCl2 + H,

Answer 1

Answer:

0.49 mol

Explanation:

Step 1: Write the balanced equation

Mg + 2 HCI ⇒ MgCl₂ + H₂

Step 2: Calculate the moles corresponding to 12 g of Mg

The molar mass of Mg is 24.31 g/mol.

$12g \times \frac{1mol}{24.31g} = 0.49mol$

Step 3: Calculate the moles of H₂ produced by 0.49 moles of Mg

The molar ratio of Mg to H₂ is 1:1. The moles of H₂ produced are 1/1 × 0.49 mol = 0.49 mol.