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2 years ago

6.8 dollars. How do you write the decimal 6.8 when it refers ti money

Mathematics

2 answers:

iragen [17]2 years ago

8 0

It would be $6.80 you automatically add a zero at the end if your using money.

Rainbow [258]2 years ago

7 0

$ 6.80.

hope that helped

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Yemi saves 150 daily how much will it save in two weeks

Leokris [45]

Answer:

$2,100

Step-by-step explanation:

In two weeks there is 14 days so, I times 150 by 14 which is 2100.

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3 years ago

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At a supermarket potatoes cost 0.39 per pound. If a 10-pound bag costs 2.79,how much money will you save if you buy the 10-pound

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How many diagonals can be constructed from one vertex of an n-gon? State your answer in terms of n and, of course, justify your

natulia [17]

Answer:

$The \ total \ number \ of \ distinct \ diagonals \ in \ a \ polygon \ with \ n \ sides= \dfrac{n \times (n - 3)}{2}$

Step-by-step explanation:

A diagonal is defined in geometry as a line connecting to two non adjacent vertices.

Therefore, the minimum number of sides a polygon must have in order to have a diagonal n - 3 sides as the 3 comes from the originating vertex and the other two adjacent vertices

Given that the polygon has n sides, the number of diagonals that can be drawn from each of those n sides gives the total number of diagonals as follows;

Total possible diagonals = n × (n - 3)

However, half of the diagonals drawn within the polygon are the same diagonals drawn in reverse. Therefore, the total number of distinct diagonals that can be drawn in a polygon is given as follows;

$The \ total \ number \ of \ distinct \ diagonals \ in \ a \ polygon \ with \ n \ sides= \dfrac{n \times (n - 3)}{2}$

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3 years ago

Can someone help me please? Thanks!

nydimaria [60]

Help you with what? where’s the problem?

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3 years ago

Find the multiplicative inverse of 3 − 2i. Verify that your solution is corect by confirming that the product of

leonid [27]

Answer:

$\frac{3}{13} + \frac{2i}{13}$

Step-by-step explanation:

The multiplicative inverse of a complex number y is the complex number z such that (y)(z) = 1

So for this problem we need to find a number z such that

(3 - 2i) ( z ) = 1

If we take z = $\frac{1}{3-2i}$

We have that

$(3- 2i)\frac{1}{3-2i} = 1$ would be the multiplicative inverse of 3 - 2i

But remember that 2i = √-2 so we can rationalize the denominator of this complex number

$\frac{1}{3-2i } (\frac{3+2i}{3+2i } )=\frac{3+2i}{9-(4i^{2} )} =\frac{3+2i}{9-4(-1)} =\frac{3+2i}{13}$

Thus, the multiplicative inverse would be $\frac{3}{13} + \frac{2i}{13}$

The problem asks us to verify this by multiplying both numbers to see that the answer is 1:

Let's multiplicate this number by 3 - 2i to confirm:

$(3-2i)(\frac{3+2i}{13}) = \frac{9-4i^{2} }{13} =\frac{9-4(-1)}{13}= \frac{9+4}{13} = \frac{13}{13}= 1$

Thus, the number we found is indeed the multiplicative inverse of 3 - 2i

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3 years ago