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Stels [109]
4 years ago
14

What is the area of parallelogram ABCD

Mathematics
2 answers:
larisa86 [58]4 years ago
7 0

Answer:

20 square units

Step-by-step explanation:

You count how many across the parallelogram is (which is 4) and you count how high it is (which is 5). Then you multiply 5×4* which equals 20 square units.

*The reason you do this is because base×hieght=area

Dmitriy789 [7]4 years ago
6 0

Answer:

20 square units

Step-by-step explanation:

Area of a parallelogram formula = base times height

To find the length of the base we take end points of the base and use distance formula

distance =\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Two points are (1,0) and (5,0)

Distance = \sqrt{(5-1)^2+(0-0)^2}

=\sqrt{4^2} =4

Length of base = 4 units

Now we find out the height between B (1,0) and D (1,5)

Height =\sqrt{(1-1)^2+(5-0)^2}=\sqrt{5^2}= 5

Height = 5

Area of the parallelogram = base times height

= 4 \cdot 5= 20

So area = 20 square units

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Find the orthogonal complement W⊥ of W and give a basis for W⊥. W = x y z : x = 1 2 t, y = − 1 2 t, z = 6t.
igor_vitrenko [27]

Answer:

W⊥= (a, b, c)

a = v - (1/2)w

b = v

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Basis for W⊥ = <(1,1,0),(-1/2,0,1)>

Step-by-step explanation:

The orthogonal complement of W is the set of vectors (a,b,c) that satisfy:

(x,y,z)·(a,b,c) = 0

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So, taking into account that x=12t, y=-12t and z=6t, the equation above is equal to:

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W⊥ = v(1,1,0) + w(-1/2,0,1)

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