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The distance between two villages is 0.625 km. Find the length in centimetres between the two villages on a map with a scale of

seropon [69]

Answer:

3125 cm

Step-by-step explanation:

The distance between two villages is 0.625 km. Find the length in centimetres between the two villages on a map with a scale of 1:5000.

We are given the scale of

1: 5000

This means

1 km = 5000 cm

Hence:

1 km = 5000cm

0.625 km = x cm

Cross Multiply

x cm = 0.625 × 5000 cm

x cm = 3125 cm

Therefore, the length in centimetres between the two villages is 3125cm

5 0

2 years ago

Evaluate the radical.<br><br> 3√27<br><br> Enter the answer in the box.

igor_vitrenko [27]

The answer is 3

Hope this Helped :T

3 0

2 years ago

Claire accepted a new job at a company with a contract guaranteeing annual raises. Let S

TiliK225 [7]

Answer:

6 years

Step-by-step explanation:

First, you need to write an equation for this problem. I'll write it in slope intercept:

y = mx + b

where m is the slope and b is the y-intercept

To find m, do (change in y/change in x):

using (2, 59000) and (5, 72500),

(72500 - 59000) / (5 - 2)

= 13500 / 3

= 4500

So we have y = 4500x + b

To find b, plug in one of the points into the equation with the slope:

using (2, 59000),

y = 4500x + b

59000 = 4500(2) + b

59000 = 9000 + b

50000 = b

So now you have an equation: y = 4500x + 50000. Now that there is an equation, just insert the given y-value and solve:

when y = 77000

y = 4500n + 50000

= 77000 = 4500x + 50000

= 27000 = 4500x

= 6 = x

So, when Claire's Salary is 77000, her number of years at the company is 6.

6 0

3 years ago

A random sample of 864 births in a state included 426 boys. Construct a 95% confidence interval estimate of the proportion of bo

oksian1 [2.3K]

Using the z-distribution, it is found that the 95% confidence interval is (0.46, 0.526), and it does not provide strong evidence against that belief.

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which:

$\pi$ is the sample proportion.

z is the critical value.

n is the sample size.

In this problem, we have a 95% confidence level, hence $\alpha = 0.95$ , z is the value of Z that has a p-value of $\frac{1+0.95}{2} = 0.975$ , so the critical value is z = 1.96.

We have that a random sample of 864 births in a state included 426 boys, hence the parameters are given by:

$n = 864, \pi = \frac{426}{864} = 0.493$

Then, the bounds of the interval are given by:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.493 - 1.96\sqrt{\frac{0.493(0.507)}{864}} = 0.46$

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.493 + 1.96\sqrt{\frac{0.493(0.507)}{864}} = 0.526$

The 95% confidence interval estimate of the proportion of boys in all births is (0.46, 0.526). Since the interval contains 0.506, it does not provide strong evidence against that belief.

More can be learned about the z-distribution at brainly.com/question/25890103

4 0

2 years ago

Whick error did she do and what the correct answer

marusya05 [52]

Answer:

The second one. The -2y should have been +2y

Step-by-step explanation:

a negative multiplied by a negative gives you a positive

8 0

3 years ago

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