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Vinvika [58]
2 years ago
6

Heyy! i’ll give brainliest please help

Mathematics
1 answer:
Elis [28]2 years ago
7 0

Answer:

C

FILLER FILLER FILLER FILLER

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45/14 as a decimal rounded to the nearest 10th
ozzi

Answer:

3.2

Step-by-step explanation:

3.21428571429 is the exact answer and rounded to the nearest tenth is the first number after the decimal.

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2 years ago
Why is the decimal in 125.6 there how did it get there?
irakobra [83]

Answer:

I’m not sure. If your joking or.

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2 years ago
Write a division problem that has a 3-digit dividend and a divisor between 10 and 20. Show how to solve it by drawing a quick pi
stich3 [128]

Answer:

In the division problem,

The number which is divided is called dividend,

While, the number which divides, is called divisor,

Let dividend = 150 ( a three digit number ),

Divisor = 15 ( a number between 10 and 12 ),

So, the problem would be,

150\div 15

In the below figure,

Take a grid that shows 150,

Divide this grid such that each box represents 15,

Thus, there are such 10 boxes,

That is,

150\div 15 = 10

7 0
2 years ago
Read 2 more answers
Farad wrote the expression 32 - 8f to represent
motikmotik
Look at this and you will be surprised on how it helps many like you that’s a key answer

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2 years ago
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F(1)=-12, f(n)=2f(n-1) <br> find first 4 terms
amid [387]
<h3>First four terms are:   -12, -24, -48, -96</h3>

============================================

Explanation:

The notation f(1) = -12 tells us that the first term is -12.

The equation f(n) = 2*f(n-1) indicates that we're multiplying the (n-1)th term by 2 to get the nth term. Basically we multiply each term by 2 to get the next term.

-12*2 = -24

-24*2 = -48

-48*2 = -96

So the first four terms are -12, -24, -48, -96.

-----------------------------------

Alternative Approach

f(1) = -12 .... first term

f(n) = 2*f(n-1) ... nth term recursive formula

f(2) = 2*f(2-1) ... plug in n = 2

f(2) = 2*f(1)

f(2) = 2*(-12) ... plug in f(1) = -12

f(2) = -24 ... second term

f(n) = 2*f(n-1) .... resetting for the next computation

f(3) = 2*f(3-1) ... plug in n = 3

f(3) = 2*f(2)

f(3) = 2*(-24)  ... plug in f(2) = -24

f(3) = -48 .... third term

f(n) = 2*f(n-1) ... one more reset

f(4) = 2*f(4-1) .... plug in n = 4

f(4) = 2*f(3)

f(4) = 2*(-48) ... plug in f(3) = -48

f(4) = -96 ... fourth term

We get the first four terms to be -12, -24, -48, -96, which was the same as earlier.

4 0
2 years ago
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