(12.61,15.04) 15.04=a(12.61)^2+b(12.61)+c well, for 3 variables, we need equations and therefor 3 points
maybe we are supposed to assume it starts at (0,0) so then 0=a(0)^2+b(0)+c 0=c so then 6.48=a(4.28)^2+b(4.28) 15.04=a(12.61)^2+b(12.61)
solve for a by subsitution first equation, minut a(4.28)^2 from both sides 6.48-a(4.28)^2=b(4.28) divide both sides by 4.28 (6.48/4.28)-4.28a=b sub that for b in other equation
15.04=a(12.61)^2+b(12.61) 15.04=a(12.61)^2+((6.48/4.28)-4.28a)(12.61) expand 15.04 =a(12.61)^2+(81.7128/4.28)-53.9708a minus (81.7128/4.28) both sides 15.04-(81.7128/4.28)=a(12.61)^2-53.9708a 15.04-(81.7128/4.28)=a((12.61)^2-53.9708) (15.04-(81.7128/4.28))/(((12.61)^2-53.9708))=a that's the exact value of a to find b, subsitute to get (6.48/4.28)-4.28((15.04-(81.7128/4.28))/(((12.61)^2-53.9708)))=b
if we aprox a≈-0.038573167896199 b≈1.6791118501845 so then the equation is y=-0.038573167896199x²+1.6791118501845x
