Answer:
13 cm
Step-by-step explanation:
AC=BD=13 cm
Here we must see in how many different ways we can select 2 students from the 3 clubs, such that the students <em>do not belong to the same club. </em>We will see that there are 110 different ways in which 2 students from different clubs can be selected.
So there are 3 clubs:
- Club A, with 10 students.
- Club B, with 4 students.
- Club C, with 5 students.
The possible combinations of 2 students from different clubs are
- Club A with club B
- Club A with club C
- Club B with club C.
The number of combinations for each of these is given by the product between the number of students in the club, so we get:
- Club A with club B: 10*4 = 40
- Club A with club C: 10*5 = 50
- Club B with club C. 4*5 = 20
For a total of 40 + 50 + 20 = 110 different combinations.
This means that there are 110 different ways in which 2 students from different clubs can be selected.
If you want to learn more about combination and selections, you can read:
brainly.com/question/251701
Answer:
Sixth graders: 14
Seventh graders: 28
Eighth graders: 28
Step-by-step explanation:
To solve this you just have to use a rule of three to solve the percentages, remember that the 100% will be the 70 students, and we solve each case separetly:
70 students= 100%
sixth grades= 40%
Sixth grades= (40*70)/100
Sixth graders= 28
70 students= 100%
seventh grades= 20%
seventh graders= (20*70)/100
Seventh graders=14
So if we have that the rest of the students are eighth graders, we just add up the sixth and seventh graders and withdraw them from the total:
28+14=42
70-42=28
SOwe have that the eighth graders are 28
Answer:
<h2>
</h2>
Option C is the correct option.
Step-by-step explanation:
√ 8 • √ 5
Calculate the product
Simplify the radical expression
Hope this helps...
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