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shutvik [7]
3 years ago
10

What is the slope of the line that contains (1,6) and (1,-9)

Mathematics
2 answers:
Alika [10]3 years ago
7 0
M= (y2-y1)/ (x2-x1)

Plug the points in.

-9-6/1-1

-15/0 or -15. The slope of the line is -15.

I hope this helped you!

Brainliest answer would be greatly appreciated!
Simora [160]3 years ago
4 0
The formula for slope is (y2 - y1) / (x2 - x1).
Substitute your values, and you get (-9 - 6) / (1 - 1), or -15 / 0
Because anything divided by zero is undefined, The line is vertical, so it has no slope. The answer is undefined
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Given klmn is a trapezoid, kl = mn, m<1 = m<2, lm/kn = 8/9, pklmn = 132. Find: the length of the legs
Ilia_Sergeevich [38]

Answer:

The length of legs lm, mn, and lk is 32 while that of kn is 36.

Step-by-step explanation:

The diagram is attached in the answer.

As both the angles are equal thus the two forms isosceles triangles. This is true because the converse of base angle theorem is applicable here. The theorem clearly states that when a trapezoid is divided by the diagonal, it forms two set of angles where m<1=m<2 and m<lmk=m<nmk

This leads the two set of legs such as

\dfrac{lm}{kn}=\dfrac{8}{9}

Or this could be written as

lm=8x\\kn=9x

Now the remaining two sides are given as

lk=lm as this form an isosceles triangle so

lk=8x

Similarly

mn=lm\\

Or

mn=8x

Now the perimeter is given as

\text{perimeter}=lm+mn+kn+lk\\

Here perimeter is given as 132 so this gives:

\text{perimeter}=lm+mn+kn+lk\\132=8x+8x+8x+9x\\132=33x\\x=\dfrac{132}{33}\\x=4

So the four legs are of length as given below:

lm=8x=8\times 4=32\\mn=8x=8\times 4=32\\lk=8x=8\times 4=32\\kn=9x=9\times4=36

So the length of legs lm, mn, and lk is 32 while that of kn is 36.

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Svetlanka [38]
84/100 which would then be 42/50 which will then be 21/25
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3 years ago
Read 2 more answers
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