Answer:
(5,-4)
Step-by-step explanation:
If reflected over the x-axis, the quadrilateral would be in the fourth quadrant. N' would be at (1,-1) and P' at (6,-1). To reflect, look at the y-coordinate of the point and turn it to negative. With point Q, it's at (5,4) so we just flip the 4 to -4 and that's our point! (5,-4)
Answer: True
Solution:
Rearrange the equation to the LHS:
[x^2 + 8x + 16] · [x^2 – 8x + 16] - (x^2 – 16)^2 = 0
Factoring x^2+8x+16
x^2 - 4x - 4x - 16
= (x-4) • (x-4)
= = (x+4)2
So now we have an equation
(x + 4)^2 • (x - 4)^2 - (x^2 - 16)^2 = 0
Step 2: Evaluate the following:
(x+4)2 = x^2+8x+16
(x-4)2 = x^2-8x+16
(x^2-16)2 = x^4-32x^2+256
(x^2+8x+16) (x^2-8x+16 ) - (x^4-32x^2+256 )
0 = 0
Hence True
Answer:
C
Step-by-step explanation:
In division when bases are same you do top exponent minus bottom exponent.
So here you do t^(12-6) which is t^6.
Answer:
I'm pretty sure A is the correct answer :)
(x-2)(x^4+3) is a polynomial
You'll need to convert both speeds into yards per minute.
12 mph = 12 mph 1760 yd 60 min
---------- * ------------ * ----------
1 mile 1 hr
Note that "miles" cancels. So does "hours." Finish this work.
Then convert 4.4 ft/sec into yards per minute.
Then, finally, compare your two rates via subtraction of the smaller from the larger.
