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shutvik [7]
2 years ago
10

What is the slope of the line that contains (1,6) and (1,-9)

Mathematics
2 answers:
Alika [10]2 years ago
7 0
M= (y2-y1)/ (x2-x1)

Plug the points in.

-9-6/1-1

-15/0 or -15. The slope of the line is -15.

I hope this helped you!

Brainliest answer would be greatly appreciated!
Simora [160]2 years ago
4 0
The formula for slope is (y2 - y1) / (x2 - x1).
Substitute your values, and you get (-9 - 6) / (1 - 1), or -15 / 0
Because anything divided by zero is undefined, The line is vertical, so it has no slope. The answer is undefined
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Select the correct answer. Which equation, when solved, gives 8 for the value of x? OA. +3 = =+14 OB. 5-9=31-12 OC. 21-2=r-4 OD.
34kurt

Answer:

B

Step-by-step explanation:

i did it and it’s right

8 0
2 years ago
Express 2x+1/(x-2)(x²+1) as a partial fraction.
Oduvanchick [21]

Answer:

Partial fraction = 1/(x-2) - x/(x^2+1)

Step-by-step explanation:

Question:

Express 2x+1/(x-2)(x²+1) as a partial fraction.

Note: it will be assumed that there was a typo in the interpretation of parentheses to mean

(2x+1) / ( (x-2)(x^2+1) )

Let

(2x+1) / ( (x-2)(x^2+1) ) = A/(x-2) + (Bx+C)/(x^2+1) .........................(0)

(2x+1) / ( (x-2)(x^2+1) ) = (A(x^2+1)+(Bx+C)(x-2)) / ( (x-2)(B/(x^2+1) )

(2x+1) / ( (x-2)(x^2+1) ) = (Ax^2+A+Bx^2+(C-2B)x-2C) / ( (x-2)(B/(x^2+1) )

(2x+1) / ( (x-2)(x^2+1) ) = ( (A+B)x^2+(C-2B)x+A-2C ) / ( (x-2)(B/(x^2+1) )

Match numerators

2x+1 = (A+B)x^2+(C-2B)x+A-2C

Match coefficients,

A+B = 0 ..................(1)

-2B+C = 2 .................(2)

A-2C = 1 ...................(3)

Solve for A, B and C

Substitute A from (1) in (3)

-B - 2C =1  

transpose and solve for B

B = -2C-1  ....................(4)

Substitue B from (4) in (2)

-2(-2C-1) + C = 2  

simplify

5C = 2-2 = 0

C=0  ..........................(5)

substitute (5)  in (4)

B = -2C-1 = -1  ...............(6)

Substitue (6) in (1)

A+(-1) = 0

A=1 .............................(7)

Using values from (7), (6) and (5) to substitute in (0)

we get

(2x+1) / ( (x-2)(x^2+1) ) = 1/(x-2) - x/(x^2+1)

as the required partial fraction

7 0
3 years ago
Read 2 more answers
Alex wants to find out how many ducks there are in a park.
Strike441 [17]

Answer:

It should be 62

Step-by-step explanation:

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5 0
2 years ago
I don’t understand this at all
Romashka [77]

Answer:

a) the midpoint is (1.5, 2.5)

b) the line is y = -(7/3)*x + 6.

Step-by-step explanation:

a)

Suppose we have two values, A and B, the mid-value between A and B is:

(A + B)/2

Now, if we have a segment with endpoints (a, b) and (c, d), the midpoint will be in the mid-value of the x-components and the mid-value of the y-components, this means that the midpoint is:

( (c + a)/2, (b + d)/2)

a) Then if the endpoints of the segment are (-2, 1) and (5, 4), the midpoint of this segment will be:

( (-2 + 5)/2, (1 + 4)/2) = (3/2, 5/2) = (1.5, 2,5)

The midpoint of the segment is (1.5, 2.5)

b)

Now we want to find the equation of a perpendicular line to our segment, that passes through the point (1.5, 2.5).

First, if we have a line:

y = a*x + b

A perpendicular line to this one will have a slope equal to -(1/a)

So the first thing we need to do is find the slope of the graphed segment.

We know that for a line that passes through the points (a, b) and (c, d) the slope is:

slope = (c - a)/(d - b)

Then the slope of the segment is:

slope = (4 - 1)/(5 - (-2)) = 3/7

Then the slope of the perpendicular line will be:

s = -(7/3)

Then the perpendicular line will be something like:

y = -(7/3)*x + d

Now we want this line to pass through the point (1.5, 2.5), then we can replace the values of this point in the above equation, and solve for d.

2.5 = -(7/3)*1.5 + d

2.5 + (7/3)*1.5 = d = 6

Then the line is:

y = -(7/3)*x + 6

7 0
3 years ago
Use the distributive property to write an expression equivalent to 5 times(3 plus 4)
Sergeeva-Olga [200]
5x(3+4) = (5x3)+(5x4)
6 0
3 years ago
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